Swift：在switch語句中使用比較運算符

Question

我試圖創建一個Switch語句（Swift），它在case大於給定數字時返回一個String。我知道這可以用「if」或「else if」語句來完成，但我正在用Switch語句完成此操作。可以這樣做嗎？或者是一個Switch語句無法利用「大於」比較運算符？

var score = 101 
var letterGrade = "" 

switch score{ 
    case >100: 
    letterGrade = "A+ With Extra Credit" 
case 90...100: 
    letterGrade = "A" 
case 80...89: 
    letterGrade = "B" 
case 70...79: 
    letterGrade = "C" 
case 60...69: 
    letterGrade = "D" 
default: 
    letterGrade = "Incomplete" 
} 

Answer 1

是一個簡單的解決方案，將其綁定到這樣一個常數：

var score = 101 
var letterGrade = "" 

switch score{ 
case let x where x > 100: 
    letterGrade = "A+ With Extra Credit" 
case 90...100: 
    letterGrade = "A" 
case 80...89: 
    letterGrade = "B" 
case 70...79: 
    letterGrade = "C" 
case 60...69: 
    letterGrade = "D" 
default: 
    letterGrade = "Incomplete" 
} 

這作品完全一樣，你需要