MySQL第二個格式化日期時間

Question

如何將第二個轉換爲mysql中的格式化日期時間？我有一個查詢來獲得第二個日期差異。即

SELECT TIMESTAMPDIFF(SECOND, '2012-06-03 13:13:55', '2012-06-06 15:20:18') sec 

現在我需要這種轉換秒日期時間SQL。可能嗎？或者有在mysql中獲得DATETIME任何功能領域與格式化選項的區別就像

SELECT DATEDIFF('%m %D, %Y %H...', '2012-06-03 13:13:55', '2012-06-06 15:20:18') sec 

所以我的預期結果爲：1 mon 5 day 13 hour 3 sec

Answer 1

退房此功能date_format(date, format)date_format spec

Answer 2

我想你想這一點。這裏默認日期指定'2008-01-02'。

SELECT DATE_ADD('2008-01-02', INTERVAL TIMESTAMPDIFF(SECOND, '2012-06-03 13:13:55', '2012-06-06 15:20:18') SECOND); 

Answer 3

這似乎是工作

SELECT 
TIMESTAMPDIFF(SECOND, '2012-06-03 13:13:55', '2012-06-06 15:20:18') secs, 
TIMESTAMPDIFF(MINUTE, '2012-06-03 13:13:55', '2012-06-06 15:20:18') mins, 
TIMESTAMPDIFF(HOUR, '2012-06-03 13:13:55', '2012-06-06 15:20:18') hours, 
TIMESTAMPDIFF(DAY, '2012-06-03 13:13:55', '2012-06-06 15:20:18') days, 
TIMESTAMPDIFF(MONTH, '2012-06-03 13:13:55', '2012-06-06 15:20:18') months, 
TIMESTAMPDIFF(YEAR, '2012-06-03 13:13:55', '2012-06-06 15:20:18') years 

給出結果行

secs mins hours days months years 
266783 4446 74  3  0  0 

現在你可以做任何你與那些結果喜歡

現在，您可以使用剛剛秒結果列來創建你的輸出使用PHP如下所示： -

<?php 
// of course get this from the result set not a hard coded value 
$secs = 266783; 
$days = date('d', $secs); 

$secs -= $days*24*60*60; 
$hours = date('H', $secs); 

$secs -= $hours*60*60; 
$mins = date('m', $secs); 

$secs -= $mins*60; 
$seconds = date('s', $secs); 

echo sprintf('%d Days %d Hours %d Minutes %d Seconds', $days, $hours, $mins, $seconds); 

這將輸出

4 Days 2 Hours 12 Minutes 23 Seconds