Drupal 7選擇查詢與連接entity_id

Question

我想離開entity_id離開，但只是收到一個錯誤，沒有細節。

Drupal中的entity_id是否有退出的技巧？

$query = db_query('SELECT COUNT(n.field_feed_vehicle_code_value) FROM {field_data_field_feed_vehicle_code} n LEFT JOIN {field_data_field_feed_vehicle_date_used} du ON n.entity_id = du.entity_id WHERE n.field_feed_vehicle_code_value = :utilization AND du.field_feed_vehicle_date_used = :utilization_date', array(':utilization' => $fieldVehicleCode, ':utilization_date' => $fieldDVIRDate))->fetchField(); 

我發現其他關於左連接的問題，但沒有真正在entity_id上。我也發現這Drupal 7 select query with joins但這種解決方案也沒有工作。

$query = db_select('node', 'n'); 
$query->leftJoin('field_data_field_feed_vehicle_code', 'vc', 'n.nid = vc.entity_id'); 
$query->leftJoin('field_data_field_feed_vehicle_date_used', 'du', 'n.nid = du.entity_id'); 
$query 
->fields('n', array('nid')) 
->fields('vc.field_feed_vehicle_code_value', $fieldVehicleCode , '=') 
->fields('du.field_feed_vehicle_date_used', $fieldDVIRDate , '=') 
->condition('type', 'dvir_utilization_feed') 
->condition('status', 1) 
->execute(); 
$num = $query->rowCount(); 

Answer 1

我相信你想使用

->condition('vc.field_feed_vehicle_code_value', $fieldVehicleCode , '=') 
->condition('du.field_feed_vehicle_date_used', $fieldDVIRDate , '=') 

，因爲這是不是爲->fields

Answer 2

正確的語法，我結束了有錯誤的字段名稱和不得不做db_query，雖然我會有首選的db_select。

$query = db_query('SELECT COUNT(vc.field_feed_vehicle_code_value) 
            FROM {node} n 
            LEFT JOIN {field_data_field_feed_vehicle_code} vc ON n.nid = vc.entity_id 
            LEFT JOIN {field_data_field_feed_vehicle_date_used} du ON n.nid = du.entity_id 
            WHERE vc.field_feed_vehicle_code_value = :utilization 
            AND du.field_feed_vehicle_date_used_value = :utilization_date', 
            array(':utilization' => $fieldVehicleCode, ':utilization_date' => $fieldDVIRDate))->fetchField(); 


      $utilization = $query;