2013-04-02 58 views
1

有沒有辦法使用JDOM查找後代元素,就像使用jQuery一樣?使用JDOM查找後代元素

我試圖讓序列元素這份XML文檔:

<getEmployeesXMLResponse xmlns="http://tempuri.org/"> 
    <getEmployeesXMLResult> 
     <xs:schema id="NewDataSet" xmlns:xs="http://www.w3.org/2001/XMLSchema" 
      xmlns="" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata"> 
      <xs:element name="NewDataSet" msdata:IsDataSet="true" 
       msdata:MainDataTable="ListOfEmployees" 
       msdata:UseCurrentLocale="true"> 
       <xs:complexType> 
        <xs:choice minOccurs="0" maxOccurs="unbounded"> 
         <xs:element name="ListOfEmployees"> 
          <xs:complexType> 
           <xs:sequence> 
            <xs:element name="name" type="xs:string" minOccurs="0" /> 
            <xs:element name="department" type="xs:string" 
             minOccurs="0" /> 
           </xs:sequence> 
          </xs:complexType> 
         </xs:element> 
        </xs:choice> 
       </xs:complexType> 
      </xs:element> 
     </xs:schema> 
     <diffgr:diffgram xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1" 
      xmlns:msdata="urn:schemas-microsoft-com:xml-msdata"> 
      <DocumentElement xmlns=""> 
       <ListOfEmployees diffgr:id="ListOfEmployees1" 
        msdata:rowOrder="0"> 
        <name>Paul</name> 
        <department>Sales</department> 
       </ListOfEmployees> 
       <ListOfEmployees diffgr:id="ListOfEmployees2" 
        msdata:rowOrder="1"> 
        <name>Bob</name> 
        <department>Marketing</department> 
       </ListOfEmployees> 
      </DocumentElement> 
     </diffgr:diffgram> 
    </getEmployeesXMLResult> 
</getEmployeesXMLResponse> 

目前我在做這個:

 Element currentEl = document.getRootElement(); 
     do { 
      currentEl = currentEl.getChildren().get(0); 
     } while (currentEl.getName() != "sequence"); 

但我想一定有一個更好的辦法。

謝謝您的建議

回答

2

使用的XPath,在這裏讀了它:JavaDoc for XPathFactory和一些關於這裏:GitHub Wiki

底線是你想有表達編譯的XPath「//XS:序列 「和命名空間Namespace.getNamespace( 」XS「,」 http://www.w3.org/2001/XMLSchema「)

rolfl

+0

感謝。我用' Namespace.getNamespace(「xs」,「w3.org/2001/XMLSchema」)取代了我的代碼; XPathExpression xpath = XPathFactory.instance()。compile(「// xs:sequence」,Filters.element());元素currentEl = xpath.evaluateFirst(document); '但現在我得到了「錯誤500:javax.servlet.ServletException:java.lang.IllegalArgumentException:帶有前綴'xs'的名稱空間尚未被聲明。」有任何想法嗎? –

+0

您必須在編譯操作中包含xs命名空間(對變量映射爲null):XPathExpression xpath = XPathFactory.instance()。compile(「// xs:sequence」,Filters.element(),null,xs ); – rolfl

+0

必須爲XPath表達式的上下文聲明名稱空間,而不僅僅是XML文檔 – rolfl