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我正在嘗試使用休眠創建以下查詢。構建一個存在的子查詢與休眠
select * from item
where exists (
select 1
from metadatavalue mv
where mv.dspace_object_id=item.uuid
and text_value='No Date'
);
我有困難使用hibernate對象構造子查詢。
下面的代碼爲我工作
Session session = (Session) context.getDBConnection().getSession();
Criteria criteria = session.createCriteria(Item.class, "item");
criteria.add(Restrictions.sqlRestriction("exists (select 1 from metadatavalue mv where mv.dspace_object_id=this_.uuid and text_value='No Date')"));
我想創建此查詢與Hibernate對象。
Session session = (Session) context.getDBConnection().getSession();
Criteria criteria = session.createCriteria(Item.class, "item");
DetachedCriteria subcriteria = DetachedCriteria.forClass(MetadataValue.class);
subcriteria.add(???)
criteria.add(Subqueries.exists(subcriteria));
我不確定從子查詢中引用item.uuid(屬性名稱「id」)的正確方法。
如果我嘗試以下
Criteria criteria = session.createCriteria(Item.class, "item");
DetachedCriteria subcriteria = DetachedCriteria.forClass(MetadataValue.class,"mv");
subcriteria.add(Property.forName("mv.dspace_object_id").eqProperty("item.uuid"));
criteria.add(Subqueries.exists(subcriteria));
System.out.println("xx" + criteria.list().size());
我收到以下錯誤
java.lang.NullPointerException
at org.hibernate.loader.criteria.CriteriaQueryTranslator.getProjectedTypes(CriteriaQueryTranslator.java:401)
at org.hibernate.criterion.SubqueryExpression.createAndSetInnerQuery(SubqueryExpression.java:152)
at org.hibernate.criterion.SubqueryExpression.toSqlString(SubqueryExpression.java:68)
at org.hibernate.loader.criteria.CriteriaQueryTranslator.getWhereCondition(CriteriaQueryTranslator.java:419)
at org.hibernate.loader.criteria.CriteriaJoinWalker.<init>(CriteriaJoinWalker.java:123)
at org.hibernate.loader.criteria.CriteriaJoinWalker.<init>(CriteriaJoinWalker.java:92)
at org.hibernate.loader.criteria.CriteriaLoader.<init>(CriteriaLoader.java:95)
at org.hibernate.internal.SessionImpl.list(SessionImpl.java:1604)
at org.hibernate.internal.CriteriaImpl.list(CriteriaImpl.java:374)
at org.dspace.core.Test.main(Test.java:37)
[
還不測試,但這個答案似乎是相關的:http://stackoverflow.com/questions/23519115/hibernate-criteria-with-exists-clause –
@BramLuyten,我所見到的例子,但我無法爲我的例子工作。我添加了更多的細節來說明我收到的錯誤。 – terrywb
您需要在已確定的條件上設置投影,以僅選擇一列:例如,「subcriteria.setProjection(Projections.id())」。 –