閱讀和使用Ajax

Question

我試圖從API返回信息的XML響應（BBB實際上）看起來它的響應，如：

<?xml version="1.0"?> 
<response> 
    <returncode>SUCCESS</returncode> 
    <meetingID>ldapreader</meetingID> 
    <attendeePW>accounts123</attendeePW> 
    <moderatorPW>accounts456</moderatorPW> 
    <createTime>1485524358342</createTime> 
    <voiceBridge>24686</voiceBridge> 
    <dialNumber>613-555-1234</dialNumber> 
    <createDate>Fri Jan 27 14:39:18 CET 2017</createDate> 
    <hasUserJoined>false</hasUserJoined> 
    <duration>0</duration> 
    <hasBeenForciblyEnded>false</hasBeenForciblyEnded> 
    <messageKey>duplicateWarning</messageKey> 
    <message> 
     This conference was already in existence and may currently be in progress. 
    </message> 
</response> 

爲Chrome瀏覽器說，這個XML文件沒有出現有任何樣式信息與之有關

我寫這個是有一些文章中，我在此網站上發現一個腳本的基礎，但我堅持......

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script> 
<script> 

    function myCall() { 
     var request = $.ajax({ 
      url: "<?php echo $fulllink; ?>", 
      type: "GET",    
      dataType: "xml" 
     }); 

     request.done(function(xml) { 
        // Parse the xml file and get data 
     var xmlDoc = $.parseXML(xml), 
      $xml = $(xmlDoc); 
     $xml.find('response').each(function() { 
      $("#mybox").append($(this).text() + "<br />"); 
     }); 
      // $("#mybox").html(xml);   
     }); 

     request.fail(function(jqXHR, textStatus) { 
      alert("Request failed: " + textStatus); 
     }); 
    } 
</script> 
     <style type="text/css"> 
      #mybox { 
       width: 300px; 
       height: 250px; 
       border: 1px solid #999; 
      } 
     </style> 
<input type="button" value="Update" onclick="myCall()" /> 
    <div id="mybox"> </div> 

不管我試圖找到（響應或返回碼，消息...）我的div保持空白，我沒有看到Chrome的調試工具中的任何錯誤。我可以看到XHR請求罰款...

也許有人知道更深的knowledgde可以幫助我嗎？
感謝您的燈光！ 塞德里克

Answer 1

您可以通過使用jQuery.parseXML()。其中做到了這一點使用瀏覽器來創建一個有效的XML文檔的本地解析功能。然後可以將此文檔傳遞給jQuery以創建可以遍歷和操作的典型jQuery對象。

使用XML字符串創建jQuery對象並獲取 節點的值。

var xml="<?xml version="1.0"?> 
<response> 
    <returncode>SUCCESS</returncode> 
    <meetingID>ldapreader</meetingID> 
    <attendeePW>accounts123</attendeePW> 
    <moderatorPW>accounts456</moderatorPW> 
    <createTime>1485524358342</createTime> 
    <voiceBridge>24686</voiceBridge> 
    <dialNumber>613-555-1234</dialNumber> 
    <createDate>Fri Jan 27 14:39:18 CET 2017</createDate> 
    <hasUserJoined>false</hasUserJoined> 
    <duration>0</duration> 
    <hasBeenForciblyEnded>false</hasBeenForciblyEnded> 
    <messageKey>duplicateWarning</messageKey> 
    <message> 
     This conference was already in existence and may currently be in progress. 
    </message> 
</response>"; 
    xmlDoc = $.parseXML(xml), 
     $xml = $(xmlDoc), 
     $meetingID = $xml.find("meetingID"); 


$("#anotherElement").append($meetingID.text()); 

Answer 2

隨着simpleXML，這是因爲讀取XML，然後訪問它通過一個簡單的內容閱讀對象一樣簡單。

<?php 

$xml="<?xml version='1.0'?> 
<response> 
    <returncode>SUCCESS</returncode> 
    <meetingID>ldapreader</meetingID> 
    <attendeePW>accounts123</attendeePW> 
    <moderatorPW>accounts456</moderatorPW> 
    <createTime>1485524358342</createTime> 
    <voiceBridge>24686</voiceBridge> 
    <dialNumber>613-555-1234</dialNumber> 
    <createDate>Fri Jan 27 14:39:18 CET 2017</createDate> 
    <hasUserJoined>false</hasUserJoined> 
    <duration>0</duration> 
    <hasBeenForciblyEnded>false</hasBeenForciblyEnded> 
    <messageKey>duplicateWarning</messageKey> 
    <message> 
     This conference was already in existence and may currently be in progress. 
    </message> 
</response>"; 


$xmlString=simplexml_load_string($xml); 
echo $xmlString->returncode[0]; 


?>