從多個字符串提取特定數據

一直在玩這個。還沒有清理它。它基本上做nslookup做的。從文本文件中獲取（或多個）主機名並返回相應的IP地址。從多個字符串提取特定數據

def getIPAddresses(file): 
    emptyList = [] 
    someString = ".com" 
    with open(file, "r+") as output: 
     for line in output: 
      emptyList.append(line) 
      my_new_list = [x.strip() + someString for x in emptyList] 
     return(my_new_list) 


def lookup(): 
    try: 
     while True: 
      enterSomething = input("Enter something: ") 
      if os.path.exists(enterSomething): 
       for n in getIPAddresses(enterSomething): 
        ip_info = socket.getaddrinfo(n, 80) 
        b = list(["nslookup of " + str(n) +"\n"] + ip_info +(["\n" + "Result of " +str(n)])) 
        values = ''.join(str(v) for v in b) 
        abc = values+ "\n" 
        print() 
        print(abc) 
       break 
      elif not os.path.exists(enterSomething): 
       print("No such file or directory " + str(enterSomething))  
    except(UnicodeError): 
     print("")

所以，如果我有以下的文本文件：

www.google 
www.espn

它將返回

nslookup of www.google.com 
(<AddressFamily.AF_INET: 2>, 0, 0, '', ('172.217.1.68', 80))(<AddressFamily.AF_INET6: 23>, 0, 0, '', ('2607:f8b0:4006:808::2004', 80, 0, 0)) 
Result of www.google.com 


nslookup of www.espn.com 
(<AddressFamily.AF_INET: 2>, 0, 0, '', ('199.181.133.5', 80)) 
Result of www.espn.com

我的問題是，是有辦法，我只能提取相應的www.google.com等ip地址，例如172.217.1.68和2607:f8b0:4006:808::2004等？

來源

2016-08-05 Kevin R.

你怎麼樣只打印接口的信息，而不是做所有的字符串連接？ –

所以你的代碼返回一個元組，元組可以像列表一樣索引。

這裏是我測試

google = socket.getaddrinfo('www.google.com', 80) 
google[0][4] 
returns ('74.125.141.104', 80)

從而獲得相關的IP地址做

google[0][4][0]

得到

'74.125.141.104'

來源

2016-08-05 13:00:08 ynot269

從多個字符串提取特定數據

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