Python：老虎機代碼錯誤

我是在ide ide中使用python的初學者，我正在嘗試編寫老虎機程序。它運行不正常，我知道它與無限循環有關，但我不確定如何修復該循環，以便代碼正常運行。有任何想法嗎？Python：老虎機代碼錯誤

import random 

coins = 1000 
wager = 2000 

print "Slot Machine" 
print "You have",coins, "coins." 
print "Press 0 to exit, any other number to play that coins per spin." 

while wager>coins: 
    print "Your Wager is greater than the number of coins you have.", 
    wager = input("") 

while ((coins>0) and (wager!= 0)): 
    x = random.randint(0,10) 
    y = random.randint(0,10) 
    z = random.randint(0,10) 
    print x, 
    print y, 
    print z 

if (x==y) and (x==z): 
    coins = (coins + wager)*100 
    print "You won",wager*100,". You now have" , coins, "coins per spin." 
    print "Press 0 to exit, any other number to play that many coins per spin." 
elif (x==y and x==z) or (x!=y and x==z) or (x!=y and y==z): 
    coins = coins + wager*10 
    print "You won" ,wager*10,". You now have", coins, "coins." 
    print "Press 0 to exit, any other number to play that coins per spin." 
else: 
    coins = coins - wager 
    print "You won" ,wager,". You now have", coins, "coins." 
    print "Press 0 to exit, any other number to play that coins per spin.", 

wager = input("") 

while wager>coins: 
    print "Your Wager is greater than the number of coins you have.", 
    wager = input("")

來源

2014-01-06 User.Name

好吧，你可能誤解了循環。這個代碼可能是你想要的：

import random 

coins = 1000 
wager = 2000 

print "Slot Machine" 

while coins > 0: 
    print "You have",coins, "coins." 
    print "Press 0 to exit, any other number to play that coins per spin." 
    wager = input("") 
    if coins == 0: 
     break 
    while wager>coins: 
     print "Your Wager is greater than the number of coins you have.", 
     wager = input("") 
    x = random.randint(0,10) 
    y = random.randint(0,10) 
    z = random.randint(0,10) 
    print x, 
    print y, 
    print z 

    if x==y and x==z: 
     coins = (coins + wager)*100 
     print "You won",wager*100,". You now have" , coins, "coins per spin." 
     print "Press 0 to exit, any other number to play that many coins per spin." 
    elif x==y or x == z: 
     coins = coins + wager*10 
     print "You won" ,wager*10,". You now have", coins, "coins." 
     print "Press 0 to exit, any other number to play that coins per spin." 
    else: 
     coins = coins - wager 
     print "You lost" ,wager,". You now have", coins, "coins." 
     print "Press 0 to exit, any other number to play that coins per spin.",

請注意，現在一切都在一個循環內，檢查您的硬幣是否大於零？在隨機數生成循環之前，永遠不會退出並繼續執行程序的其餘部分。

來源

2014-01-06 23:33:45 riri

一件重要的事情！不要使用「輸入」功能。當你調用輸入時，它實際上評估你放入的任何東西，就好像它是Python代碼一樣。這意味着如果我輸入「shutil; shutil.rmtree（'/'，false）」我可以刪除所有文件。相反，你可以寫'wager = int（raw_input（「」））'，它將輸入作爲一個字符串，然後將其轉換爲一個整數。 – riri

如果我使用@riri發佈的調整後的代碼，輸出將會是類似於 '老虎機你有1000個硬幣。按0退出，其他任何數字都會在每次旋轉時播放該硬幣。 100 你輸了100。你現在有900個硬幣。按0退出，其他任何數字都會在每次旋轉時播放該硬幣。你有900個硬幣。按0退出，其他任何數字都會在每次旋轉時播放該硬幣。' 我該如何擺脫這樣一句話：「按0退出，其他任何數字都可以在每次旋轉時播放這些硬幣，您有900個硬幣。」我只想要一行說'按0退出，其他任何數字都可以在每次旋轉時播放這些硬幣。' –

只需在循環運行之前移動語句以使其發生。如果您剛剛開始學習編程，我建議您編寫一個程序，通過使用一個循環來打印從1到10，然後從10到1的數字。我認爲它會幫助教你如何循環工作。 – riri

Python：老虎機代碼錯誤

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