JOIN查詢，在hasMany關聯中建立條件

Question

我正在使用CakePHP 2.3.6。在一個項目中，我使用hasMany關聯中的JOIN查詢來搜索一些數據。我的條件應該是：

User.gender='male' AND User.country='USA' 
AND 
(Education.level='under_graduate' AND Education.result >= 3.5 AND Education.institute='college 1') 
AND 
(Education.level='graduate' AND Education.result >= 3 AND Education.institute='college 2') 

我試了一下：

$this->paginate['User']['conditions']['AND']['User.gender']='male'; 
$this->paginate['User']['conditions']['AND']['User.country']='USA'; 
$this->paginate['User']['joins'][]=array('table'=>'educations','alias'=>'Education','type'=>'INNER','conditions'=>array('Education.user_id=User.id')); 
$this->paginate['User']['conditions']['AND'][0]['AND']['Education.result >= ']=3.5; 
$this->paginate['User']['conditions']['AND'][0]['AND']['Education.level']='under_graduate'; 
$this->paginate['User']['conditions']['AND'][0]['AND']['Education.institute']='college 1'; 
$this->paginate['User']['conditions']['AND'][1]['AND']['Education.result >= ']=3; 
$this->paginate['User']['conditions']['AND'][1]['AND']['Education.level']='graduate'; 
$this->paginate['User']['conditions']['AND'][1]['AND']['Education.institute']='college 2'; 

我產生這種情況陣：

[User] => Array 
    (
     [conditions] => Array 
      (
       [AND] => Array 
        (
         [User.gender] => male 
         [User.country] => USA 
         [0] => Array 
          (
           [AND] => Array 
            (
             [Education.result >= ] => 3.5 
             [Education.level] => under_graduate 
             [Education.institute] => college 1 
            ) 

          ) 

         [1] => Array 
          (
           [AND] => Array 
            (
             [Education.result >= ] => 3 
             [Education.level] => graduate 
             [Education.institute] => college 2 
            ) 

          ) 

        ) 

      ) 

     [joins] => Array 
      (
       [0] => Array 
        (
         [table] => educations 
         [alias] => Education 
         [type] => INNER 
         [conditions] => Array 
          (
           [0] => Education.user_id=User.id 
          ) 

        ) 

      ) 

    ) 

但是，當我搜索使用這個條件下，返回我空結果數組，但我知道在db中有一些符合這些條件的。

那麼，這裏有什麼問題？我該怎麼辦 ？請幫幫我。

謝謝。

Answer 1

所以我明白你需要找到一個有兩個教育的用戶。在您的AND條件下，您可以看到您正在試圖找到Educations.institute，這將等同於「大學1」和「大學2」，這是不可能的。所以，有一種方法可以通過爲同一個表添加多個連接來找到它。像這樣：

$options['conditions']['User.gender']='male'; 
    $options['conditions']['User.country']='USA'; 
    $options['joins'][]=array(
     'table'=>'educations', 
     'alias'=>'FirstEd', 
     'type'=>'INNER', 
     'conditions'=>array('FirstEd.user_id=User.id') 
    ); 
    $options['joins'][]=array(
     'table'=>'educations', 
     'alias'=>'SecondEd', 
     'type'=>'INNER', 
     'conditions'=>array('SecondEd.user_id=User.id') 
    ); 
    $options['conditions']['AND'][0]['FirstEd.result']=3.5; 
    $options['conditions']['AND'][0]['FirstEd.level'] = 'under_graduate'; 
    $options['conditions']['AND'][0]['FirstEd.institute']='college 1'; 
    $options['conditions']['AND'][1]['SecondEd.result']=3; 
    $options['conditions']['AND'][1]['SecondEd.level']='graduate'; 
    $options['conditions']['AND'][1]['SecondEd.institute']='college 2'; 

    $this->Paginator->settings = $options; 
    $users = $this->Paginator->paginate('User'); 

不是最好的解決方案，但它適用於我。

Answer 2

您的查詢是使用所有AND語句，因此不可能實現。 由於字段不能同時具有這兩個值，因此不會與Education.level = 'under_graduate'和'Education.level' = 'graduate'連續。 您需要添加或在您的查詢，例如：

User.gender='male' AND User.country='USA' 
AND 
(
    (Education.level='under_graduate' AND Education.result >= 3.5 AND Education.institute='college 1') 
    OR 
    (Education.level='graduate' AND Education.result >= 3 AND Education.institute='college 2') 
) 

我只是額外增加了一套支架，改變了AND或有關教育的兩個分句之間。 希望你應該能夠將它翻譯成CakePHP格式，它將起作用！