不能與PHP

Question

打印MySQL查詢的結果，我有以下MySQL查詢

$jokerQuery = mysql_query("SELECT `Joker sport`, 
     COUNT(`Joker sport`) AS jokerCount 
     FROM Profiles 
     WHERE `CompetitorID` = 5 
     GROUP BY `Joker sport` 
     ORDER BY COUNT(`Joker sport`) DESC 
     LIMIT 1 
    "); 

返回在phpMyAdmin

Joker sport | jokerCount 
8   | 8 

以下結果我想下面的PHP將顯示的結果，但它不起作用。我應該寫什麼來回應結果？

$jokerResult = mysql_fetch_array($jokerQuery); 
echo $jokerResult['Joker sport']; 
echo $jokerResult['jokerCount']; 

Answer 1

試試這個，在mysql_fetch_array添加MYSQL_ASSOC爲常量：

$jokerResult = mysql_fetch_array($jokerQuery, MYSQL_ASSOC); 
echo $jokerResult['Joker sport']; 
echo $jokerResult['jokerCount']; 

Answer 2

你還可以嘗試：

$jokerResult = mysql_fetch_array($jokerQuery, MYSQL_ASSOC); 
print_r($jokerResult); 

看到列名。