SQL服務器GROUP BY只顯示第一個匹配

Question

我有以下表，並希望將通過

[name]    [phone] 
doniking   081222222222 
doni    081222222222 
Bambang Gentholet 081111111111 
Bambang   081111111111 

我想要得到這樣的結果：

[name]    [phone] 
doniking   081222222222 
Bambang Gentholet 081111111111 

Answer 1

試試這個

SELECT [name],[phone] 
FROM (
     SELECT *,Row_Number() Over (Partition By phone Order By (Select Null)) AS RN 
     FROM Table1 
    ) AS T 
Where RN = 1 
OFFSET n ROWS 

您可以用您的自定義值替換n ...

Row_Number

Answer 2

試試這個

SELECT MAX(name), phone FROM <TableName> group by phone 

編輯：膠印

SELECT MAX(name), phone FROM <TableName> group by phone 
order by phone offset 10 rows 
FETCH NEXT 5 ROWS ONLY; 

Check this進一步的細節。

Answer 3

試試這個

SELECT name, 
    phone 
FROM (SELECT *, 
      Row_number() 
      OVER( 
       partition BY phone 
       ORDER BY name) row_num -- or you can have order by (select null) 
    FROM table1) t 
WHERE row_num = 1