PHP表格：只填充字段的成功電子郵件

現在一直在努力解決這個問題。基本上我有6個字段，姓名，電子郵件，電話，地點，日期和預算。姓名和電子郵件是唯一必填字段。當我收到電子郵件時，我也會看到其他字段。是否可以只接收已填充的字段？PHP表格：只填充字段的成功電子郵件

這是代碼;

<?php 
// get posted data into local variables 
$EmailFrom = "[email protected]"; 
$EmailTo = "[email protected]"; 
$Subject = "My form"; 
$Name = Trim(stripslashes($_POST['Name'])); 
$Email = Trim(stripslashes($_POST['Email'])); 
$Phone = Trim(stripslashes($_POST['Phone'])); 

$Location = Trim(stripslashes($_POST['Location'])); 
$Date = Trim(stripslashes($_POST['Date'])); 
$Budget = Trim(stripslashes($_POST['Budget'])); 

// validation 
$validationOK=true; 
if (!$validationOK) { 
    print "<meta http-equiv=\"refresh\" content=\"0;URL=#\">"; 
    exit; 
} 

$userip = ($_SERVER['X_FORWARDED_FOR']) ? $_SERVER['X_FORWARDED_FOR'] : $_SERVER['REMOTE_ADDR']; 

// prepare email body text 
$Body = ""; 
$Body .= "Location: "; $Body .= $Location; $Body .= "\n"; 
$Body .= "Date: "; $Body .= $Date; $Body .= "\n"; 
$Body .= "Budget: "; $Body .= $Budget; $Body .= "\n"; 

$Body .= "Name: "; $Body .= $Name; $Body .= "\n"; 
$Body .= "Email: "; $Body .= $Email; $Body .= "\n"; 
$Body .= "Phone: "; $Body .= $Phone; $Body .= "\n"; 
$Body .= "User's IP: ". $userip; 

// send email 
$success = mail($EmailTo, $Subject, $Body, "From: <$EmailFrom>"); 

// redirect to success page 
if ($success){ 
    print "<meta http-equiv=\"refresh\" content=\"0;URL=#\">"; 
} 
else{ 
    print "<meta http-equiv=\"refresh\" content=\"0;URL=#\">"; 
} 
?>

來源

2012-06-08 Jake

當'

使用empty來檢查，如果值被張貼或不：

$Phone = !empty($_POST['Phone']) ? trim(stripslashes($_POST['Phone'])) : false;

再後來$Phone將是錯誤的，如果它沒有填寫，你可以這樣做：

if($Phone) 
    $Body .= "Phone: "; $Body .= $Phone; $Body .= "\n";

來源

2012-06-08 00:57:41 Paulpro

不錯的保羅在更改'isset（）'爲'empty（）' – deex

@dqlopez謝謝哈哈。如果不是您對這個問題的評論，我不會接受它。 – Paulpro

工作很好！非常感謝。 – Jake

您可以簡單地進行檢查，看看值是否在那裏。你可以這樣做：

if (!empty($Location) { $Body .= "Location: "; $Body .= $Location; $Body .= "\n"; }

等。這是說，如果位置不爲空，然後執行該代碼

來源

2012-06-08 00:57:53 chadpeppers

是的，只是你Concat的字段前添加一個檢查身體，如：

if(!$Location) 
{ 
    $Body .= "Location: "; $Body .= $Location; $Body .= "\n"; 
} 
/*You can also use empty like: */ 
if(!empty($Date)) 
{ 
    $Body .= "Location: "; $Body .= $Date; $Body .= "\n"; 
} 
/*Continue here*/

來源

2012-06-08 00:58:57

不需要$ Location！=「」即使它工作。如果（$ Location）沒有任何東西，它將返回false。如果是，它會變成真 – chadpeppers

謝謝，將編輯答案反映這 –

-1

if (isset($_POST['phone'] && !empty($_POST['phone']){ 
    $phone = $_POST['phone']; 
    //add $phone to email body 
}

來源

2012-06-08 01:01:47 Joshua

爲什麼不只是在第一次檢查中添加到電子郵件？而不是設置額外的$ has_phone變量？並做額外的檢查？ –

夠真實。將追加。 – Joshua

PHP表格：只填充字段的成功電子郵件

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