Question

我有以下幾點，我正在創建一個動態鏈接，我堅持拼接的分裂。

link = "<li><span id='number'>" + link.split(" ")[0] + ".</span>" // Adding a "peroid" character after the reason number and make it bold 
     + "<a href='#" + reasonTitle + "' " // Open link tag off adding href with relevant reference 
     + "onclick=\"_gaq.push([\'_trackEvent\', \'" + experimentConversionReference + "\', \'ReasonClicked\', \'" + reasonTitleSpaces + "\'])\;\">" // Adding event tracking for google 
     + link.split(/\d/)[1] // Add back on the back end of the split string 
     + "</a>" // Close link tag off 
     + "</li>"; 

以上我想抓住從[1]和最多打印數組中的一切，我怎麼能做到這一點。更具體line 4？

我不希望是做

link.split(/\d/)[1] + link.split(/\d/)[2] + link.split(/\d/)[3] + link.split(/\d/)[] 

等。

Answer 1

你並不需要分割，剛剛獲得空格後的字符串部分：

link.substr(link.indexOf(" ") + 1); 

Answer 2

斯普利特和加入，但不包括第一項：

var joined = link.split(/\d/); 
joined .shift(); // remove first item 
joined .join(''); // join the array 

，然後用它喜歡：

link = "<li><span id='number'>" + link.split(" ")[0] + ".</span>" // Adding a "peroid" character after the reason number and make it bold 
     + "<a href='#" + reasonTitle + "' " // Open link tag off adding href with relevant reference 
     + "onclick=\"_gaq.push([\'_trackEvent\', \'" + experimentConversionReference + "\', \'ReasonClicked\', \'" + reasonTitleSpaces + "\'])\;\">" // Adding event tracking for google 
     + joined // Add back on the back end of the split string 
     + "</a>" // Close link tag off 
     + "</li>"; 

Answer 3

使用此：

link.split(/\d/).slice(1).join('')