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我在本地機器上的Windows Azure和Yii應用程序中有一個SQL數據庫。我使用PHP 5.4.9和php_pdo_sqlsrv_54_nts.dll驅動程序。Azure SQL Server和Yii Active Record
Main.php：
'db'=>array(
'connectionString' => 'sqlsrv:Server=tcp:MYSERVER.database.windows.net,1433;Database=MYDB;',
'username' => 'admin',
'password' => 'pass',
'charset' => 'utf8',
),
當我試圖連接到SQL Server的Yii拋出此異常：
CDbCommand failed to execute the SQL statement: SQLSTATE[42S02]: [Microsoft][SQL Server Native Client 11.0][SQL Server]Invalid object name 'sys.extended_properties'.. The SQL statement executed was: SELECT t1.*, columnproperty(object_id(t1.table_schema+'.'+t1.table_name), t1.column_name, 'IsIdentity') AS IsIdentity, CONVERT(VARCHAR, t2.value) AS Comment FROM [INFORMATION_SCHEMA].[COLUMNS] AS t1 LEFT OUTER JOIN sys.extended_properties AS t2 ON t1.ORDINAL_POSITION = t2.minor_id AND object_name(t2.major_id) = t1.TABLE_NAME AND t2.class=1 AND t2.class_desc='OBJECT_OR_COLUMN' AND t2.name='MS_Description' WHERE t1.TABLE_NAME='users' AND t1.TABLE_SCHEMA='dbo'
它顯示在GII或簡單<?php echo User::model()->findAllByPk(1)->email;?>字符串頁面上。
我在做什麼錯？
UPD： user.php的
class User extends CActiveRecord {
public static function model($className = __CLASS__)
{
return parent::model($className);
}
public function tableName()
{
return 'users';
}
public function rules()
{
return array(
array('email, password', 'required')
);
}
public function attributeLabels()
{
return array(
'id' => 'ID',
'email' => 'Email'
);
}
}
表users只包含id，email和password領域。
此代碼有效！
$connection=Yii::app()->db;
$sql = "INSERT INTO users (email, password) VALUES ('[email protected]', 'example')";
$command=$connection->createCommand($sql);
$some = $command->execute();
如何在Yii Active Record中使用SQLSRV？
你的陳述失敗了？ –
它在錯誤信息中告訴你到底是什麼問題。嘗試使用在錯誤中生成的SQL語句，並找出它的錯誤。說它不喜歡你試圖加入的'sys.extended_properties'。我很懷疑你有一個名爲'sys.extended_properties'的表。 – Pitchinnate
'<？php echo User :: model（） - > findAllByPk（1） - > email;？>'例如。 – llvk