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有人請幫忙!這可能是一個非常簡單的錯誤,但我是PHP & MySQL的新手。我試圖根據用戶的日期選擇從數據庫中檢索信息。我使用了一些在YouTube上找到的例子,用jquery將輸入發佈到php頁面,並在html頁面上顯示來自php的檢索值。但是,它似乎只返回下面的else if語句。非常感謝您的幫助!
的Html下面:
<div id="customDateRange">
<h2>Welcome <?php echo $companyName ?></h2>
<h3 style="color:#ff0000">This is currently under development</h3>
<h4>Please specify the dates you would like to view below:</h4>
<label for="dateStart">Start Date</label>
<input class="datePick" id="dateStart" name="dateStart" type="text"/>
<label for="dateEnd">End Date</label>
<input class="datePick" ud="dateEnd" type="text"/>
<input id="getDateRange" type="submit" value="Display Report" />
<div id="fromDatabase"></div>
</div>
的Javascript下面:
$('.datePick').datepicker({ minDate: new Date(2013, 3 - 1, 1), dateFormat: 'yy-mm-dd' });
$('input#getDateRange').on('click', function(){
var startDate = $('input#dateStart').val();
if ($.trim(startDate) != '') {
$.post('../../includes/dateRangeDB.php', function(data, status){
$('div#fromDatabase').text(data);
});
}
});
PHP下面:
<?php
if (isset($_POST['dateStart']) === true && empty($_post['dateStart']) === false) {
$query = mysql_query("
SELECT TotalCost FROM adwords_reporting WHERE CampaignID = 'CAMP020' AND Date IN ('" . mysql_real_escape_string(trim($_POST['dateStart'])) . "')
");
echo "Total Cost: " . (mysql_num_rows($query) !== 0) ? mysql_result($query, 0, 'TotalCost') : 'Date Not Found';
}
else if (isset($_POST['dateStart']) === false) {
echo "WTF MAN!";
}
else {
echo "It seems there is an issue";
}
?>
謝謝您的幫助!
建議。如果您有元素ID,請不要在其之前添加標籤名稱。 '$(「#getDateRange」)。在(...' – 2013-03-22 21:04:41
它看起來並不像你加入後變量到$ .post的電話。這個問題是jQuery的帖子...你應該重提到文檔 – rnirnber 2013-03-22 21:07:24
@RicardoLohmann謝謝,我應該知道比包含標籤名稱更好* smh * – soulglow1985 2013-03-25 16:10:57