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請幫助我米使用此代碼匹配url值的用戶名和密碼登錄認證
和Java代碼，
public class AndroidHTTPRequestsActivity extends Activity implements OnClickListener {
private EditText usernameEditText;
private EditText passwordEditText;
private Button sendGetReqButton;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
usernameEditText = (EditText) findViewById(R.id.main_username_editText);
passwordEditText = (EditText) findViewById(R.id.main_password_editText);
sendGetReqButton = (Button) findViewById(R.id.main_sendGetReq_button);
sendGetReqButton.setOnClickListener(this);
}
public void onClick(View v) {
if(v.getId() == R.id.main_sendGetReq_button) {
// Get the values given in EditText fields
String givenUsername = usernameEditText.getText().toString();
String givenPassword = passwordEditText.getText().toString();
System.out.println("Given usernames is :" + givenUsername + " Given password is :" + givenPassword);
// Pass those values to connectWithHttpGet() method
connectWithHttpGet(givenUsername, givenPassword);
}
}
private void connectWithHttpGet(String givenUsername, String givenPassword) {
class HttpGetAsyncTask extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... params) {
String email = params[0];
String pwd = params[1];
System.out.println("email is :" + email + " pwd is :" + pwd);
HttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet("http://ipadress/folder/filename.php?command=CMD_LOGIN&email=name&pwd=00");
try {
HttpResponse httpResponse = httpClient.execute(httpGet);
System.out.println("httpResponse");
// that comes as the httpResponse
InputStream inputStream = httpResponse.getEntity().getContent();
InputStreamReader inputStreamReader = new InputStreamReader(inputStream);
BufferedReader bufferedReader = new BufferedReader(inputStreamReader);
StringBuilder stringBuilder = new StringBuilder();
String bufferedStrChunk = null;
while((bufferedStrChunk = bufferedReader.readLine()) != null){
stringBuilder.append(bufferedStrChunk);
}
System.out.println("Returning value of doInBackground :" + stringBuilder.toString());
return stringBuilder.toString();
} catch (ClientProtocolException cpe) {
System.out.println("Exception generates caz of httpResponse :" + cpe);
cpe.printStackTrace();
} catch (IOException ioe) {
System.out.println("Second exception generates caz of httpResponse :" + ioe);
ioe.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
if(result.equals("1"))
{
Toast.makeText(getApplicationContext(), "HTTP GET is working...", Toast.LENGTH_LONG).show();
}else{
Toast.makeText(getApplicationContext(), "Invalid...", Toast.LENGTH_LONG).show();
}
}
}
HttpGetAsyncTask httpGetAsyncTask = new HttpGetAsyncTask();
httpGetAsyncTask.execute(givenUsername, givenPassword);
}
}
後。其中認證並獲得響應logcat中創建登錄頁面喜歡這個。如何將結果值相匹配登錄Sucess
if(result.equal(""))
表明我應該使用結果比較？我嘗試了value==1，它不起作用。
07-19 13:54:26.509: I/System.out(13951): Given usernames is :name Given password is :00
07-19 13:54:26.519: I/System.out(13951): email is :name pwd is :00
07-19 13:54:27.689: I/System.out(13951): httpResponse
07-19 13:54:27.689: I/System.out(13951): Returning value of doInBackground :<?xml version="1.0" encoding="ISO-8859-1"?><command><value>1</value><email>[email protected]</email><id>100001</id><first_name>Sue</first_name><last_name>Stappler</last_name><photo>images/teacher.png</photo><total_students>2</total_students><student_list> <student> <id>200001</id> <first_name>John</first_name> <last_name>Mathew</last_name> <photo>images/student.png</photo> </student> <student> <id>200002</id> <first_name>Steve</first_name> <last_name>Jobs</last_name> <photo>images/student.png</photo> </student></student_list><description_title>Login Success</description_title><description_message>Correct username and password</description_message><session_id>ecaf065b3213179afcd0d9895691505c</session_id></command>