得到一個表的主鍵列

Question

我要確保這是獲得PK的名稱，架構，表名和列名指定表的名稱

SELECT i.name AS IndexName, 
     (SELECT SCHEMA_NAME([schema_id]) FROM sys.[tables] WHERE [object_id] = ic.OBJECT_ID) SchemaName, 
     OBJECT_NAME(ic.OBJECT_ID) AS TableName, 
     COL_NAME(ic.OBJECT_ID,ic.column_id) AS ColumnName 
    FROM sys.indexes AS i 
INNER JOIN sys.index_columns AS ic 
    ON i.OBJECT_ID = ic.OBJECT_ID 
    AND i.index_id = ic.index_id 
WHERE i.is_primary_key = 1 
    AND OBJECT_NAME(ic.OBJECT_ID) = 'MyTable' 

的正確的方式，我相信這是工作

SELECT i.name AS IndexName, 
     SCHEMA_NAME([schema_id]) SchemaName, 
     OBJECT_NAME(ic.OBJECT_ID) AS TableName, 
     COL_NAME(ic.OBJECT_ID,ic.column_id) AS ColumnName, 
     ic.key_ordinal 
    FROM sys.indexes AS i 
INNER JOIN sys.index_columns AS ic 
    ON i.OBJECT_ID = ic.OBJECT_ID 
    AND i.index_id = ic.index_id 
INNER JOIN sys.[tables] st 
    ON st.[object_id] = ic.OBJECT_ID 
WHERE i.is_primary_key = 1 
    AND SCHEMA_NAME([schema_id]) = 'auth' 
    AND OBJECT_NAME(ic.OBJECT_ID) = 'Profile' 

Answer 1

有很多方法可以做到這一點，沒有人「正確的方式」。這個可以工作，但是一些附帶案件會讓你失望。一些小的調整：

SELECT 
    schema_name(t.schema_id) AS SchemaName 
,t.name AS TableName 
,i.name AS IndexName 
,co.name AS ColumnName 
,ic.key_ordinal AS ColumnOrder -- [2] 
    FROM sys.tables AS t 
INNER JOIN sys.indexes AS i 
    ON i.OBJECT_ID = t.OBJECT_ID 
INNER JOIN sys.index_columns AS ic 
    ON i.OBJECT_ID = ic.OBJECT_ID 
    AND i.index_id = ic.index_id 
INNER JOIN sys.columns AS co 
    ON co.column_id = ic.index_column_id 
    AND co.object_id = t.object_id 
WHERE i.is_primary_key = 1 
    AND t.name = 'MyTable' 
    AND schema_name(t.schema_id) = 'dbo' -- [1] 
ORDER BY ic.key_ordinal -- [2] 

[1]，您可以指定要搜索哪些架構（的事項，如果你有超過DBO定義）

[2]涵蓋化合物（多列）索引，並顯示他們的訂單