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我試圖從表中檢索數據，我沒有從我目前使用的模型直接關係。如何在Laravel雄辯中建立三個表之間的關係？
我的數據結構：
表：帖子
- ID - 整數
- 標題 - 字符串
表：post_stacks
- ID - 整數
- POST_ID - 整數
- stack_id - 整數
表：棧
- ID - 整數
- 體 - 字符串
- 網址 - 串
我的口才模型是從post.php中（職位表），我試圖讓關聯到我的帖子的所有堆棧（從棧表）。我只想在Post.php而不是我的數據透視表（post_stacks）上聲明我的關係。
我試過hasManyThrough，但我的表結構不符合Laravel要求的需求，因爲我需要在我的Stacks表上使用外鍵。
這是我目前的執行：
post.php中
class Post extends Model
{
protected $dates = [
'created_at',
'updated_at'
];
public function user()
{
return $this->belongsTo(\App\User::class, 'user_id', 'id');
}
public function post_stacks()
{
return $this->hasMany(\App\PostStack::class);
}
public function post_os()
{
return $this->hasMany(\App\PostOS::class, 'post_id', 'id');
}
public function post_tags()
{
return $this->hasMany(\App\PostTag::class , 'post_id', 'id');
}
public function getCreatedAtAttribute($value)
{
return Carbon::parse($value)->toFormattedDateString();
}
}PostController.php
class PostController extends Controller
{
public function index()
{
$posts = Post::all();
foreach($posts as $post){
$post->user;
$post->created_at;
$posts_os = $post->post_os;
$post_stacks = $post->post_stacks;
$post_tags = $post->post_tags;
foreach($posts_os as $post_os){
$os = OS::where('id', $post_os->os_id)->first();
$post_os['body'] = $os['body'];
}
foreach($post_stacks as $post_stack){
$stack = Stack::where('id', $post_stack->stack_id)->first();
$post_stack['url'] = $stack['url'];
$post_stack['body'] = $stack['body'];
}
foreach($post_tags as $post_tag){
$tag = Tag::where('id', $post_tag->tag_id)->first();
$post_tag['body'] = $tag['body'];
}
}
return response()->json($posts);
}
}我的JSON數據響應
[
{
"id":1,
"title":"Laravel + XAMPP",
"user_id":1,
"description":"I'll take you through the entire process of setting up a development environment for Laravel using XAMPP.",
"created_at":"Jun 12, 2017",
"updated_at":"2017-06-12 08:55:02",
"user":{
"id":1,
"name":"EpIEhg7ciO",
"email":"[email protected]",
"created_at":"2017-06-12 08:55:02",
"updated_at":"2017-06-12 08:55:02"
},
"post_os":[
{
"id":1,
"post_id":1,
"os_id":1,
"created_at":"2017-06-12 08:55:02",
"updated_at":"2017-06-12 08:55:02",
"body":"Windows"
}
],
"post_stacks":[
{
"id":1,
"post_id":1,
"stack_id":1,
"created_at":"2017-06-12 08:55:02",
"updated_at":"2017-06-12 08:55:02",
"url":"laravel.svg",
"body":"Laravel"
},
{
"id":2,
"post_id":1,
"stack_id":2,
"created_at":"2017-06-12 08:55:02",
"updated_at":"2017-06-12 08:55:02",
"url":"xampp.svg",
"body":"XAMPP"
}
],
"post_tags":[
{
"id":1,
"post_id":1,
"tag_id":1,
"created_at":"2017-06-12 08:55:02",
"updated_at":"2017-06-12 08:55:02",
"body":"laravel"
},
{
"id":2,
"post_id":1,
"tag_id":2,
"created_at":"2017-06-12 08:55:02",
"updated_at":"2017-06-12 08:55:02",
"body":"xampp"
}
]
},
{
"id":2,
"title":"Laravel + Vagrant",
"user_id":1,
"description":"I'll take you through the entire process of setting up a development environment for Laravel using Vagrant.",
"created_at":"Jun 12, 2017",
"updated_at":"2017-06-12 08:55:02",
"user":{
"id":1,
"name":"EpIEhg7ciO",
"email":"[email protected]",
"created_at":"2017-06-12 08:55:02",
"updated_at":"2017-06-12 08:55:02"
},
"post_os":[
{
"id":2,
"post_id":2,
"os_id":1,
"created_at":"2017-06-12 08:55:02",
"updated_at":"2017-06-12 08:55:02",
"body":"Windows"
},
{
"id":3,
"post_id":2,
"os_id":2,
"created_at":"2017-06-12 08:55:02",
"updated_at":"2017-06-12 08:55:02",
"body":"Mac OS X"
},
{
"id":4,
"post_id":2,
"os_id":3,
"created_at":"2017-06-12 08:55:02",
"updated_at":"2017-06-12 08:55:02",
"body":"Linux"
}
],
"post_stacks":[
{
"id":3,
"post_id":2,
"stack_id":1,
"created_at":"2017-06-12 08:55:02",
"updated_at":"2017-06-12 08:55:02",
"url":"laravel.svg",
"body":"Laravel"
},
{
"id":4,
"post_id":2,
"stack_id":3,
"created_at":"2017-06-12 08:55:02",
"updated_at":"2017-06-12 08:55:02",
"url":"vagrant.png",
"body":"Vagrant"
}
],
"post_tags":[
{
"id":3,
"post_id":2,
"tag_id":1,
"created_at":"2017-06-12 08:55:02",
"updated_at":"2017-06-12 08:55:02",
"body":"laravel"
},
{
"id":4,
"post_id":2,
"tag_id":3,
"created_at":"2017-06-12 08:55:02",
"updated_at":"2017-06-12 08:55:02",
"body":"vagrant"
}
]
}
]我的JSON數據是正是我想要的。我只是覺得我的PostController實現效率低下，並且運行了太多的查詢。我運行的查詢太多，並且有嵌套循環。有沒有一種乾淨的方式可以使用Laravel的方法/關係之一建立關係？
謝謝！
我不太明白，你是如何與這兩種模式？有沒有外鍵建立關係？ – 75Kane
通過表名和你定義的字段。當你將它們添加到模型類時，雄辯會假設一些關於表之間關係的約定。 – btl
請記住，這隻適用於您的中間表名稱字段名稱。他們完全遵循雄辯的期望，所以你不需要「指導」如何建立關係的雄辯。 – btl