打字稿無法使用新的運營商

Question

對象的創建，以創建一個類的對象正在發生的事情而不會出現錯誤：

Answer 1

有一個snippet at TS playground

我會說，我們可以考慮一下這款接口及其實現

namespace Common.Models 
{ 
    export interface IPaginationModel { 
     PageNumber: number; 
     PageSize: number; 
     SearchText: string; 
     Ascending: boolean; 
    } 
    export class PaginationModel implements IPaginationModel { 
     constructor(
      public PageNumber: number, 
      public PageSize: number, 
      public SearchText: string, 
      public Ascending: boolean 
     ){} 
    } 
} 

，然後我們可以因此使用這樣的

// we use an Interface to assure that the type is as it should be 
// we create object which fits to IPaginationModel structure 
let paginationParams: Common.Models.IPaginationModel = { 
    PageNumber: this.pageNumber, 
    PageSize: this.pageSize, 
    SearchText: this.denominationFilter, 
    Ascending: true 
}; 

// here we use a class 
// to call its constructor 
let pagParams = new Common.Models.PaginationModel(
    this.pageNumber, 
    this.pageSize, 
    this.denominationFilter, 
    true); 

// and we can even use class as interface (as the first example) 
let paginationParamsAsClassAPI: Common.Models.PaginationModel = { 
    PageNumber: this.pageNumber, 
    PageSize: this.pageSize, 
    SearchText: this.denominationFilter, 
    Ascending: true 
}; 

，我們可以使用接口和類作爲的類型時，同時建立純JS對象（第一和第三實施例）或我們可以使用類構造函數建立這樣的例子。

檢查here