如何將目標c的完成塊轉換爲Swift？

Question

我在迅速的新嘗試客觀C座語法轉換迅速的Xcode 6.3.2

完成塊的typedef：

typealias CompletionWithBoolBlock = (Bool, NSError, NSString) -> Void 

[Model insertObjectWithTable:@"tblStudent" values:dict completion:^(BOOL success, NSError *responseError, NSString *object){ 

     if(success){ 
      NSLog(@"inserted"); 
     } 
     else 
     { 
      NSLog(@"Not inserted, %@",responseError.description); 
     } 
    }]; 

衝浪淨後，我試着用

Model.insertObjectWithTable("tblStudent", values: dict, completion:({(success:Bool,responseError:NSError, object:NSString)->(Void) in 

     if success 
      { 
       println("inserted") 
      } 
      else 
      { 
       println("Not inserted \(responseError.description)") 
      } 
     }) 
} 

和

Model.insertObjectWithTable("tblStudent", values: dict, completion:(success:Bool,responseError:NSError, object:NSString)->Void{ 

     if success 
      { 
       println("inserted") 
      } 
      else 
      { 
       println("Not inserted \(responseError.description)") 
      } 
     }) 

但它顯示我錯誤

預計 '' 分隔符

在表達式列表預計表達

Answer 1

你試過

Model.insertObjectWithTable("tblStudent", values: dict, completion:{(success:Bool, responseError:NSError, object:NSString) -> Void in 
    if success { 
     println("inserted") 
    } else { 
     println("Not inserted \(responseError.description)") 
    } 
})