查詢失敗：您的SQL語法出錯;檢查與您的MySQL相對應的手冊

由於我的服務提供商不再支持舊版本，我不得不更新到MySQL 5和PHP 5。我有一個工作網站，這個MySQL搜索工作正常。以下是放置在用戶的列表頁面上的一個包含。當我將SQL語句取出並在服務器上運行時，它會返回正確的結果。我的猜測是這與格式有關。任何想法，爲什麼我可能會得到這個錯誤？「查詢失敗：您的SQL語法出錯;檢查與您的MySQL相對應的手冊

」查詢失敗：您的SQL語法有錯誤;請查看與您的MySQL服務器版本相對應的手冊，以便在第1行「ORDER BY x.id_have LIMIT 0,30'附近使用正確的語法」

有了這個語法

<table cellpadding="15" border="0"> 
<tr> 
    <td valign="top"> 
    So far, the following members have these items which match; 
    <ul> 
    <? 
    $peoplewhomatch = mysql_query("SELECT x.id_customer, g.title Have, c.user_name as Member, g.title gwants, gg.title Has, y.id_customer x_username 
     FROM Want x 
     JOIN Want y 
      ON (y.id_sellversion,y.id_version) = (x.id_version,x.id_sellversion) 
     inner join Version as v 
      on x.id_version = v.id_version 
     inner join Version as vv 
      on y.id_version = vv.id_version 
     inner join Game as g 
      on g.id_game = vv.id_game 
     inner join Customer as c 
      on y.id_customer = c.id_customer 
     inner join Game as gg 
      on gg.id_game = v.id_game 
     WHERE x.id_have = $hid 
     ORDER BY x.id_have 
     LIMIT 0, 30")or die("Query failed: " . mysql_error()); 
    while($row = mysql_fetch_array($peoplewhomatch)) 
    { ?> 
    <span class='greenitalic'><?=$row['Member']?></span> has <span class='highshadow'><?=$row['Has']?></span> and wants <span class='ishadow'><?=$row['gwants']?></span><BR><?}?> 
    </td> 
</tr> 
</table>

來源

2013-06-27 Steve Whitlow

'... WHERE x.id_have = '$藏' ORDER BY ...'？如果'$ hid'是一個字符串，需要用單引號包裝 - ''$ hid'' – Sean

謝謝肖恩，就是這樣！ –

你可能需要包裝$hid引號，像這樣：

$peoplewhomatch = mysql_query("SELECT x.id_customer, g.title Have, c.user_name as Member, g.title gwants, gg.title Has, y.id_customer x_username 
     FROM Want x 
     JOIN Want y 
      ON (y.id_sellversion,y.id_version) = (x.id_version,x.id_sellversion) 
     inner join Version as v 
      on x.id_version = v.id_version 
     inner join Version as vv 
      on y.id_version = vv.id_version 
     inner join Game as g 
      on g.id_game = vv.id_game 
     inner join Customer as c 
      on y.id_customer = c.id_customer 
     inner join Game as gg 
      on gg.id_game = v.id_game 
     WHERE x.id_have = '$hid' 
     ORDER BY x.id_have 
     LIMIT 0, 30")or die("Query failed: " . mysql_error());

來源

2013-06-27 01:55:21

查詢失敗：您的SQL語法出錯;檢查與您的MySQL相對應的手冊

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