解析JSON與GSON不POJO？

Question

希望有從別人放在這裏一個簡單的解決方案。我知道有類似的問題，但我似乎無法修改它們與我的問題的工作。

我試圖解析對該JSON響應「的formatted_address」字符串：

{ 
    "results" : [ 
     { 
     "address_components" : [ 
      { 
       "long_name" : "Google Building 42", 
       "short_name" : "Google Bldg 42", 
       "types" : [ "premise" ] 
      }, 
      { 
       "long_name" : "1600", 
       "short_name" : "1600", 
       "types" : [ "street_number" ] 
      }, 
      { 
       "long_name" : "Amphitheatre Parkway", 
       "short_name" : "Amphitheatre Pkwy", 
       "types" : [ "route" ] 
      }, 
      { 
       "long_name" : "Mountain View", 
       "short_name" : "Mountain View", 
       "types" : [ "locality", "political" ] 
      }, 
      { 
       "long_name" : "Santa Clara County", 
       "short_name" : "Santa Clara County", 
       "types" : [ "administrative_area_level_2", "political" ] 
      }, 
      { 
       "long_name" : "California", 
       "short_name" : "CA", 
       "types" : [ "administrative_area_level_1", "political" ] 
      }, 
      { 
       "long_name" : "United States", 
       "short_name" : "US", 
       "types" : [ "country", "political" ] 
      }, 
      { 
       "long_name" : "94043", 
       "short_name" : "94043", 
       "types" : [ "postal_code" ] 
      } 
     ], 
     "formatted_address" : "Google Bldg 42, 1600 Amphitheatre Pkwy, Mountain 
    View, CA 94043, USA", 
     "geometry" : { 
      "bounds" : { 
       "northeast" : { 
        "lat" : 37.42198310000001, 
        "lng" : -122.0853195 
       }, 
       "southwest" : { 
        "lat" : 37.4214139, 
        "lng" : -122.0860042 
       } 
      }, 
      "location" : { 
       "lat" : 37.4216548, 
       "lng" : -122.0856374 
      }, 
      "location_type" : "ROOFTOP", 
      "viewport" : { 
       "northeast" : { 
        "lat" : 37.4230474802915, 
        "lng" : -122.0843128697085 
       }, 
       "southwest" : { 
        "lat" : 37.4203495197085, 
        "lng" : -122.0870108302915 
       } 
      } 
     }, 
     "place_id" : "ChIJPzxqWQK6j4AR3OFRJ6LMaKo", 
     "types" : [ "premise" ] 
     } 
    ], 
    "status" : "OK" 
    } 

當以前使用GSON我能夠解析我的結果馬上使用：

Gson gson = new Gson(); 

    JsonArray body = gson.fromJson(ResultString, JsonArray.class); 
    System.out.println(body.get(0).getAsJsonObject().get("elementnamehere").getAsString()); 

的主要的區別是我不能把這個結果放入JsonArray體。相反，（我相信，因爲它嵌套數據），我必須使它一個JSONObject，但沒有得到空，我不能解析它爲我的生活。任何簡單的方法來做到這一點，而不是做一個POJO或響應類？如果不是有人可以解釋如何/爲什麼這樣做，像這樣：

Parsing nested JSON data using GSON

Answer 1

你就要成功了，你是正確的，你需要解析JsonObject。

JsonObject body = gson.fromJson(json, JsonObject.class); 
JsonArray results = body.get("results").getAsJsonArray(); 
JsonObject firstResult = results.get(0).getAsJsonObject(); 
JsonElement address = firstResult.get("formatted_address"); 
System.out.println(address.getAsString());