將查詢結果限制爲mysql中的前10位

-1

我試圖將以下查詢結果限制爲僅前10個響應。到目前爲止，查詢完全符合我的要求 - 即按count排列按頂級系統列表排序的頂級系統。我獲得了所有31個回覆，但我只想要前10個回覆。我試圖創建一個雖然DO /結束While循環，但我無法弄清楚到底在何處放置在下面的代碼：將查詢結果限制爲mysql中的前10位

$sql = " 
SELECT HelpDesk 
    , COUNT(*) as NumSys 
    FROM `systems_17-18` 
WHERE HelpDesk <>'' 
    AND HelpDesk <> 'NONE'  
GROUP BY HelpDesk 
ORDER 
    by NumSys DESC 
"; 
$result = $conn->query($sql); 
$mycount = 0; 
if ($result->num_rows > 0) { 
// output data of each row 
echo "<table class='uk-table uk-table-condensed uk-table-hover uk-table-striped'>";   
while($row = $result->fetch_assoc()) 
{ 
$mycount ++; 

echo "<tr>" ; 
    echo "<td>"; 

    echo "<a href=" . $row['webaddress'] . " >"; 
    echo $row['SchoolDistrict'] . "</a>"; 
    echo "</td><td># " . $mycount . " " . $row['HelpDesk'] . " used by " . $row[NumSys] . " district(s)"; 
echo "</td></tr>"; 
} 

echo "</table>"; 
}

（注：上面的代碼正確生成下面的數據，但我怎麼會限制列表中只排名前10的反應用while循環ENDWHILE）在加利福尼亞州

學區使用各種幫助臺系統：？？

1 MyTechDesk used by 52 district(s) 
2 SchoolDude used by 40 district(s) 
3 WebHelpDesk used by 29 district(s) 
4 ZenDesk used by 15 district(s) 
5 SpiceWorks used by 14 district(s) 
6 KACE1000/2000 used by 13 district(s) 
7 FreshDesk used by 8 district(s) 
8 Track-IT! used by 6 district(s) 
9 Custom used by 6 district(s) 
10 HEAT (Help Desk) used by 6 district(s) 
11 SysAid used by 5 district(s) 
12 ServiceDeskPlus used by 4 district(s) 
13 GroupLink HelpDesk used by 4 district(s) 
14 Altiris used by 4 district(s) 
15 GLPI used by 3 district(s) 
16 HESK used by 3 district(s) 
17 HelpDesk used by 2 district(s) 
18 Cherwell used by 2 district(s) 
19 OPRAS used by 2 district(s) 
20 Manage Engine Service Desk used by 2 district(s) 
21 Samanage used by 1 district(s) 
22 Absolute used by 1 district(s) 
23 OTRS used by 1 district(s) 
24 SherpaDesk used by 1 district(s) 
25 Applied HelpDesk used by 1 district(s) 
26 Public School Works used by 1 district(s) 
27 iTop used by 1 district(s) 
28 Connectwise used by 1 district(s) 
29 Asana used by 1 district(s) 
30 RT/SRTS used by 1 district(s) 
31 OSTicket used by 1 district(s)

來源

2017-09-16 Chris Moggia

你有沒有考慮過使用[MySQL的LIMIT子句（HTTP：// www.mysqltutorial.org/mysql-limit.aspx）。 –

有很多問題顯示如何做到這一點，這應該作爲一個副本關閉。 –

對於未來，考慮搜索類似[「mysql中的前10位結果」]（https://www.w3schools.com/sql/sql_top.asp）。對於任何你知道如何在MS SQL谷歌如何在MySQL – Ibu

您ORDER BY語句後添加LIMIT 10。

$sql = "SELECT HelpDesk, COUNT(*) as NumSys FROM `schoolt7_systems`.`systems_17-18` WHERE HelpDesk <>'' AND HelpDesk <> 'NONE'  GROUP BY HelpDesk ORDER by NumSys DESC LIMIT 10";

編輯：從MS SQL服務器被更換到MySQL

參考：https://www.w3schools.com/sql/sql_top.asp

來源

2017-09-16 00:30:19

謝謝大家。對不起，重複的條目。我真的嘗試在發佈之前尋找答案！ –

使用LIMIT：

SELECT 
    HelpDesk, 
    COUNT(*) AS NumSys 
FROM `schoolt7_systems`.`systems_17-18` 
WHERE 
    HelpDesk <>'' AND 
    HelpDesk <> 'NONE' 
GROUP BY 
    HelpDesk 
ORDER by NumSys DESC 
LIMIT 10    -- add this to your query

來源

2017-09-16 00:31:52

將查詢結果限制爲mysql中的前10位

回答

相關問題