文件名中的特殊字符，不支持同時使用URI

Question

複製我需要從一個路徑複製文件（文件名中包含特殊字符），使用URI另一條路徑。但它會拋出一個錯誤。如果它成功複製，如果文件名不包含特殊字符。你能否告訴我如何使用特定字符的URI從一個路徑複製到另一個路徑。我已經複製下面的代碼和錯誤。

代碼： -

import java.io.*; 
import java.net.URI; 
import java.nio.ByteBuffer; 
import java.nio.channels.Channels; 
import java.nio.channels.ReadableByteChannel; 
import java.nio.channels.WritableByteChannel; 

public class test { 
    private static File file = null; 
    public static void main(String[] args) throws InterruptedException, Exception { 
     String from = "file:///home/guest/input/3.-^%&.txt"; 
     String to = "file:///home/guest/output/3.-^%&.txt"; 
     InputStream in = null; 
     OutputStream out = null; 
     final ReadableByteChannel inputChannel; 
     final WritableByteChannel outputChannel; 
     if (from.startsWith("file://")) { 
      file = new File(new URI(from)); 
      in = new FileInputStream(file); 
     } 

     if (from.startsWith("file://")) { 
      file = new File(new URI(to)); 
      out = new FileOutputStream(file); 
     } 

     inputChannel = Channels.newChannel(in); 
     outputChannel = Channels.newChannel(out); 

     test.copy(inputChannel, outputChannel); 
     inputChannel.close(); 
     outputChannel.close(); 
    } 

    public static void copy(ReadableByteChannel in, WritableByteChannel out) throws IOException { 
     ByteBuffer buffer = ByteBuffer.allocateDirect(32 * 1024); 
     while (in.read(buffer) != -1 || buffer.position() > 0) { 
     buffer.flip(); 
     out.write(buffer); 
     buffer.compact(); 
     } 
    } 
} 

錯誤： -

Exception in thread "main" java.net.URISyntaxException: Illegal character in path at index 30: file:///home/maria/input/3.-^%&.txt 
    at java.net.URI$Parser.fail(URI.java:2829) 
    at java.net.URI$Parser.checkChars(URI.java:3002) 
    at java.net.URI$Parser.parseHierarchical(URI.java:3086) 
    at java.net.URI$Parser.parse(URI.java:3034) 
    at java.net.URI.<init>(URI.java:595) 
    at com.tnq.fms.test3.main(test3.java:29) 
Java Result: 1 

感謝您尋找到這...

Answer 1

的文件名應該是%-escaped。例如，實際文件名中的空格變爲URI中的％20。

new URI("file", null, "/home/guest/input/3.-^%&.txt", null); 

見HTTP URL Address Encoding in Java：如果你使用一個構造函數與幾個參數的java.net.URI類可以爲你做到這一點。

Answer 2

你可以嘗試使用java.net.uri。