多播委託中的異常處理

Question

我有一個多播委託，我通過它調用兩種方法。如果第一個方法中存在異常並且它處理了，那麼如何繼續執行第二個方法調用？我附上下面的代碼。在下面的代碼中，第一個方法拋出異常。但我想知道如何通過多播委託調用繼續執行第二種方法。內環路

public delegate void TheMulticastDelegate(int x,int y); 
    class Program 
    { 
      private static void MultiCastDelMethod(int x, int y) 
      { 
        try 
        { 
          int zero = 0; 
          int z = (x/y)/zero; 
        } 
        catch (Exception ex) 
        {        
          throw ex; 
        } 
      } 

      private static void MultiCastDelMethod2(int x, int y) 
      { 
        try 
        { 
          int z = x/y; 
          Console.WriteLine(z); 
        } 
        catch (Exception ex) 
        { 
          throw ex; 
        } 
      } 
      public static void Main(string[] args) 
      { 
        TheMulticastDelegate multiCastDelegate = new TheMulticastDelegate(MultiCastDelMethod); 
        TheMulticastDelegate multiCastDelegate2 = new TheMulticastDelegate(MultiCastDelMethod2); 

        try 
        { 
          TheMulticastDelegate addition = multiCastDelegate + multiCastDelegate2; 

          foreach (TheMulticastDelegate multiCastDel in addition.GetInvocationList()) 
          { 
            multiCastDel(20, 30); 
          } 
        } 
        catch (Exception ex) 
        { 
          Console.WriteLine(ex.Message); 
        } 

        Console.ReadLine(); 
      } 
    } 

Answer 1

移動在try..catch：

foreach (TheMulticastDelegate multiCastDel in addition.GetInvocationList()) 
{ 
    try 
    { 
     multiCastDel(20, 30); 
    } 
    catch (Exception ex) 
    { 
     Console.WriteLine(ex.Message); 
    } 
} 

除此之外，您還願意與throw ;取代throw ex;因爲前者創建一個新的異常，這是不必要的。它應該看起來像：

private static void MultiCastDelMethod(int x, int y) 
{ 
    try 
    { 
     int zero = 0; 
     int z = (x/y)/zero; 
    } 
    catch (Exception ex) 
    { 
     throw ; 
    } 
}