如何添加和訂閱jabber條目到我的XMPP賬戶？

Question

我可以使用此代碼將Entry添加到Xmpp帳戶。我無法獲得訂閱「兩個」，而不是我得到none。

roster.createEntry("abc@xyz.com", "abc", null);

如何與存在type=both，當我訂閱進入此帳戶添加條目。我想知道xmpp publish-subscribe的功能嗎？

1. 如何獲取入站通知？
2. 如何發送出站通知？

編輯：

public void Addcontact() {  
    Roster.setDefaultSubscriptionMode(Roster.SubscriptionMode.manual); 
    Roster roster = m_connection.getRoster(); 

    if(!roster.contains("pa@ace.com")) {  try {   
      roster.createEntry("pa@ace.com", "pa", null);    
     } catch (XMPPException e) {   
      e.printStackTrace(); 
     } 
    }else { 
     Log.i("Acc = ", "contains"); 
    } 
} 

我加入這樣還是我得到在場類型=無帖子..

Answer 1

下面是我添加的另一位朋友在我的應用程序。

protected void doAddContactToListAsync(String address, String name, 
       ContactList list) throws ImException { 
      debug(TAG, "add contact to " + list.getName()); 
      Presence response = new Presence.Type.subscribed); 
      response.setTo(address); 

      sendPacket(response); 

      Roster roster = mConnection.getRoster(); 
      String[] groups = new String[] { list.getName() }; 
      if (name == null) { 
       name = parseAddressName(address); 
      } 
      try { 
       // final String name = parseAddressName(address); 
       // Log.v(tag, msg) 

       roster.createEntry(address, name, groups); 

       // If contact exists locally, don't create another copy 
       Contact contact = makeContact(name, address); 
       if (!containsContact(contact)) 
        notifyContactListUpdated(list, 
          ContactListListener.LIST_CONTACT_ADDED, contact); 
       else 
        debug(TAG, "skip adding existing contact locally " + name); 
      } catch (XMPPException e) { 
       throw new RuntimeException(e); 
      } 
     } 

只需使用必不可少的一部分

Presence response = new Presence.Type.subscribed); 
response.setTo(address); 
sendPacket(response); 

Roster roster = mConnection.getRoster(); 
roster.createEntry(address, name, groups); 

要收聽傳入的請求，註冊addPacketListener您連接

mConnection.addPacketListener(new PacketListener() { 

      @Override 
      public void processPacket(Packet packet) { 

       Presence presence = (Presence) packet; 
        if (presence.getType() == Type.subscribe) { 
        debug(TAG, "sub request from 1" + address); 
//Implement accept or reject depend on user action. 
      mContactListManager.getSubscriptionRequestListener() 
          .onSubScriptionRequest(contact); 
//or you can test with send back Presence.subscribe first and send Presence.subscribed back to requester. 


       } else {// Handle other Presence type. 
        int type = parsePresence(presence); 
        debug(TAG, "sub request from " + type); 
        contact.setPresence(new Presence(type, 
          presence.getStatus(), null, null, 
          Presence.CLIENT_TYPE_DEFAULT)); 

       } 
      } 
     }, new PacketTypeFilter(Presence.class)); 

     mConnection.connect(); 

正確的順序：

1. 用戶1送訂閱用戶2。
2. 用戶2發送訂閱並被子訂回給用戶1。
3. 用戶1發送Subsribed到user2。

另一個SO question，您可以檢查