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我想用ajax php和javacript的web服務,這個例子,但我仍然有這個錯誤。 我試了很多代碼,請別人幫我。在PHP和JavaScript中實現Web服務。
XMLHttpRequest無法加載xxxxx/login.php。請求的資源上沒有「Access-Control-Allow-Origin」標題。因此不允許原產地'null'訪問。 index.html的:1周
的index.html
<html><head>
<script src="jquery-2.1.0.js"></script>
<script src="jsjsjs.js"></script>
</head>
<body>
<div id='logindiv'>
<label>Username:</label>
<input name="username" id="username" type="text">
<label>Password:</label>
<input name="password" id="password" type="password">
<input value="Submit" name="submit" class="submit" type="submit" onclick='chk_ajax_login_with_php();'>
<div id='status'></div>
</div>
</body>
</html>
jsjsjs.js
function chk_ajax_login_with_php(){
var username=document.getElementById("username").value;
var password=document.getElementById("password").value;
var params = "username="+username+"&password="+password;
var url = "xxxxx/login.php";
$.ajax({
type: 'POST',
url: url,
dataType: 'html',
data: params,
beforeSend: function() {
document.getElementById("status").innerHTML= 'checking...' ;},
complete: function() { },
success: function(html) {
document.getElementById("status").innerHTML= html;
if(html=="success"){
window.location ="/test.php"
}
}
});
}
的login.php
<?php
if ($_POST['username'] != null and $_POST['username'] != "" and $_POST['password'] != null and $_POST['password'] != ""){
$username = $_POST['username'];
$password = $_POST['password'];
}
if($username == "youssef" and $password=="4656"){
echo "Nice";
}
else { echo "nono";}
}
?>
在請求的資源上存在[No'Access-Control-Allow-Origin'標頭可能存在重複。'爲什麼當我使用POSTMAN時沒有顯示?](http://stackoverflow.com/questions/20035101/no-access-control-allow-origin-header-is-present-on-the-requested-resource-w) – Quentin
您應該[瞭解如何正確使用標籤元素](http://www.456bereastreet.com/archive/200711/use_the_label_element_to_make_your_html_forms_accessible/)。如果沒有for屬性或者表單控件,標籤就沒用了。 – Quentin