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請原諒我下面可能濫用類別理論術語。如果我看起來有一半線索,我會判斷自己非常成功。如何簡化幾個arvals類型構造函數的「產品」類型類?
我發現自己寫了一系列的類來處理多個類型構造函數的產品。像這樣:
import Control.Applicative
-- | RWS monad.
newtype RWS r w s a = RWS {runRWS :: r -> s -> (a, s, w)}
-- | A class for unary type constructors that support a Cartesian
-- product operation.
class ProductObject f where
(***) :: f a -> f b -> f (a, b)
infixr ***
-- | Example instance of 'ProductObject'.
instance ProductObject [] where
(***) = liftA2 (,)
-- | A class for binary type constructors (read as morphisms
-- between their type parameters) that support a product morphism
-- operation.
class ProductMorphism arrow where
(****) :: arrow a b -> arrow c d -> arrow (a, c) (b, d)
infixr ****
-- | Example instance of 'ProductMorphism'.
instance ProductMorphism (->) where
f **** g = \(a, c) -> (f a, g c)
-- | A class for ternary type constructors (read as two-place
-- multiarrows @a, b -> [email protected]) with products.
class ProductMultimorphism2 arr2 where
(*****) :: arr2 a b c -> arr2 d e f -> arr2 (a, d) (b, e) (c, f)
infixr *****
-- | A class for ternary type constructors (read as two-place
-- multiarrows @a, b -> [email protected]) with products.
class ProductMultimorphism3 arr3 where
(******) :: arr3 a b c d -> arr3 e f g h -> arr3 (a, e) (b, f) (c, g) (d, h)
infixr ******
-- | Let's pretend that the 'RWS' monad was not a type synonym
-- for 'RWST'. Then an example of 'ProductMorphism3' would be:
instance ProductMultimorphism3 RWS where
f ****** g = RWS $ \(fr, gr) (fs, gs) ->
let (fa, fs', fw) = runRWS f fr fs
(ga, gs', gw) = runRWS g gr gs
in ((fa, ga), (fs', gs'), (fw, gw))
現在,這是令人討厭的幾個原因。最大的問題是我必須在我的應用程序中修改其中的一種類型以添加第三個參數,這意味着現在我必須去查找該類型的所有用途****
並將它們更改爲*****
。
我可以申請緩解這種情況嗎?我試圖瞭解GHC中的PolyKinds
是否適用於此,但(a)這很慢,(b)我聽說GHC 7.4.x中的PolyKinds
是buggy。