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我正在創建一個使用C++和QT的軟件,並且我有兩個類型的QRadioButon和一個QTabWidget。我的需要是我想從單選按鈕發送信號,我希望每當按鈕被選中時,標籤的內容就會被更改。 任何人都可以建議如何做到這一點?我試圖創建一個我的小部件類的插槽,並在那個槽中我稱爲tab類的構造函數,但問題是construtor沒有被調用。 這裏是我使用的代碼..如何將QRadioButton連接到QTabWidget?
#include <QtGui>
#include "v_lab.h"
v_lab::v_lab(QWidget *parent)
: QDialog(parent)
{
setWindowTitle("Virtual Lab");
maingroup=new QGroupBox(this);
maingroup->setTitle("Algorithms");
maingroup->setMinimumWidth(200);
maingroup->setMaximumWidth(240);
maingroup->setFlat(false);
p=new QPalette;
p->setColor(QPalette::Background,QColor(233,212,102));
setPalette(*p);
box=new QGroupBox(maingroup);
box->setFlat(false);
box->setTitle("Searching Algorithm");
linear_search=new QRadioButton("Linear Search",box);
linear_search->setChecked(1);
binary_search=new QRadioButton("Binary Search",box);
box1=new QGroupBox(maingroup);
box1->setFlat(false);
box1->setTitle("Sorting Algorithms");
bubble_sort=new QRadioButton("Bubble Sort",box1);
selection_sort=new QRadioButton("Selection Sort",box1);
box2=new QGroupBox(maingroup);
box2->setFlat(false);
box2->setTitle("Tree Algorithms");
infix_traversal=new QRadioButton("Infix Traversal",box2);
prefix_traversal=new QRadioButton("Prefix Traversal",box2);
postfix_traversal=new QRadioButton("Postfix Traversal",box2);
box3=new QGroupBox(maingroup);
box3->setFlat(false);
box3->setTitle("Graph Algorithms");
bfs=new QRadioButton("BFS",box3);
dfs=new QRadioButton("DFS",box3);
shortest_path=new QRadioButton("Shortest Path",box3);
QString string1="go to hell";
tab=new QTabWidget;
tab->addTab(new algorithm(string1),"Algorithm");
// tab->addTab(new psudo_code(),"Pseduo-Code");
tab->setMinimumWidth(250);
tab->setMaximumWidth(400);
//Layout
mainlayout=new QHBoxLayout(this);
mainlayout->addWidget(maingroup);
mainlayout->addWidget(tab);
mainlayout->addStretch();
main_left_pane_layout=new QVBoxLayout(maingroup);
main_left_pane_layout->addWidget(box);
main_left_pane_layout->addWidget(box1);
main_left_pane_layout->addWidget(box2);
main_left_pane_layout->addWidget(box3);
left_pane_box=new QVBoxLayout(box);
left_pane_box->addWidget(linear_search);
left_pane_box->addWidget(binary_search);
left_pane_box1=new QVBoxLayout(box1);
left_pane_box1->addWidget(bubble_sort);
left_pane_box1->addWidget(selection_sort);
left_pane_box2=new QVBoxLayout(box2);
left_pane_box2->addWidget(infix_traversal);
left_pane_box2->addWidget(prefix_traversal);
left_pane_box2->addWidget(postfix_traversal);
left_pane_box3=new QVBoxLayout(box3);
left_pane_box3->addWidget(bfs);
left_pane_box3->addWidget(dfs);
left_pane_box3->addWidget(shortest_path);
connect(binary_search,SIGNAL(clicked()),this,SLOT(peeyush()));
}
algorithm::algorithm(const QString &string,QWidget *parent)
: QWidget(parent)
{
label=new QLabel(string);
main_layout=new QVBoxLayout;
main_layout->addWidget(label);
main_layout->addStretch();
setLayout(main_layout);
}
/*
psudo_code::psudo_code(QWidget *parent)
: QWidget(parent)
{
label1=new QLabel("Hello Peeyush Chandel");
main_layout1=new QVBoxLayout;
main_layout1->addWidget(label1);
main_layout1->addStretch();
setLayout(main_layout1);
}
*/
void v_lab::peeyush()
{
QString string1="new string";
algorithm obj(string1);
//exit(1);
}
請學習如何插入代碼。我的眼睛流血嘗試閱讀此。其次,你不能將信號連接到構造函數,這沒有任何意義。 – teukkam 2010-08-31 14:16:39
我希望實際的代碼不會看起來這...偶然。另外,如何更改連接到單選按鈕的插槽中的選項卡*不工作? – 2010-08-31 14:23:25