我怎樣才能使這種加法更簡單？

Question

該代碼添加一組牌（在遊戲的21點）

# Rules 
print("Dont enter Ace, Jack, Queen or king in the first 4 Inputs") 
print("You will be told when to enter those") 
print("if you dont have a card just enter 0") 

# Line break 
print("") 

card1 = int(input("What is your first card: ")) 
card2 = int(input("What is your second card: ")) 
card3 = int(input("What is your third card: ")) 
card4 = int(input("What is your fourth card: ")) 


# Line break 
print("") 

# print("King = 10 \nJack = 10 \nQueen = 10 \nAce = 11 or 1 ") 
AJKQ = (input("Any Ace, jack, Queens or kings: ")) 
AJKQ2 = (input("Any Ace, jack, Queens or kings: ")) 

# Line Break 
print("") 

print(card1 + card2 + card3 + card4 + AJKQ + AJKQ2) 

代碼需要加起來得到了用戶的卡，並與王牌輸出插孔王后和國王

林還ifs和elifs不是很好，那麼最好的辦法是將它壓縮成更小的代碼？

Answer 1

print("""Dont enter Ace, Jack, Queen or king in the first 4 Inputs 
You will be told when to enter those. 
if you dont have a card just enter 0\n""") 

print(sum([int(input("what is your "+ char +" card: ")) for char in("first", "second", "third","fourth")]) + 
sum([int(input("Any Ace, jack, Queens or kings: ")) for i in range(0,2)])) 

這應該是罰款。

Answer 2

cards = ['first', 'second', 'third', 'fourth'] 
card = [] 
for value in cards: 
    card.append(int(input("What is your "+value+" card: "))) 

... 

print("".join(card) + AJKQ + AJKQ2)