棘手的問題。插入JSON數據

Question

我的JSON：

{ 
    "orders": [ 
    { 
     "id": 10, 
     "number": 10, 
     "line_items": [ 
     { 
      "id": 3, 
      "sub": "21.00", 
      "sub_tax": "0.00", 
      "total": "21.00", 
      "total_tax": "0.00", 
      "quantity": 1, 
      "tax_class": null, 
      "meta": [] 
     } 
     ] 
    } 
    ] 
} 

什麼我都不得不時刻：

$json = json_decode(file_get_contents(JSON_URL), true); 
foreach ($json as $u => $z){ 
    foreach ($z as $n => $line){ 
$number = $line['number']; 
$line_item_id = $line['line_items'][0]['id']; 
      $line_item_sub = $line['line_items'][0]['sub]; 
      $line_item_sub_tax = $line['line_items'][0]['sub_tax']; 
      $line_item_total = $line['line_items'][0]['total']; 
      $line_item_total_tax = $line['line_items'][0]['total_tax']; 
      $line_item_quantity = $line['line_items'][0]['quantity']; 
      $line_item_tax_class = $line['line_items'][0]['tax_class']; 

} 
} 

我在數據庫中插入這些DATAS在foreach結束。這裏的問題如下：

如果有多個line_items，它應該在數據庫中創建新行。僅插入：number和附加line_items。

請記住，可以說有20個不同的數據庫行創建，其中只有一個line_items，但只有其中兩個具有多個line_item數組。我怎麼能做這個工作？

我已經試過這樣的事情：

$countid = $line['line_items'][0]['id']; 
     if(count($countid) > 1){ 
      $number = $line['order_number']; 
      $line_item_id = $line['line_items'][0]['id']; 
      $line_item_sub = $line['line_items'][0]['sub']; 
      $line_item_sub_tax = $line['line_items'][0]['sub_tax']; 
      $line_item_total = $line['line_items'][0]['total']; 
      $line_item_total_tax = $line['line_items'][0]['total_tax']; 
      $line_item_quantity = $line['line_items'][0]['quantity']; 
      $line_item_tax_class = $line['line_items'][0]['tax_class']; 
     } else { 
<!-- Insert data normally --> 

但我不這麼認爲，這可能是工作。你有什麼想法，我怎麼能做到這一點？ 讓我知道我是否可以提供更多信息。謝謝！

如何我插入DATAS：

$con = mysqli_connect("111.11.111.11","username","password","database") or die('Could not connect: ' . mysql_error()); 

// prepare your insert query 
$stmt = mysqli_prepare($con, 'INSERT INTO table_name(values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names, values_names,) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)'); 

// bind the upcoming variable names to the query statement 
mysqli_stmt_bind_param($stmt, 'isssssssssssssssssssssssssssssssssssssssssssss', $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables $values_variables); 

foreach循環抓住每排約45個不同的項目。其中12個來自line_items。而在第二個foreach循環結束時，有mysqli_stmt_execute($stmt);這工作正常。需要幫助來解決我應該找到if語句或其他foreach循環的邏輯，以便每當當前number下有多個line_items數組時，我可以創建新行。

Answer 1

根據您提供的JSON字符串我假定這段代碼解決您的問題：

$json = json_decode(file_get_contents(JSON_URL), true); 
foreach ($json['orders'] as $line) { 
    foreach ($line['line_items'] as $item) { 
     // no need to distinguish between 1 or more items 
     // foreach handles both cases 
     $number    = $line['number']; 
     $line_item_id  = $item['id']; 
     $line_item_sub  = $item['sub']; 
     $line_item_sub_tax = $item['sub_tax']; 
     $line_item_total  = $item['total']; 
     $line_item_total_tax = $item['total_tax']; 
     $line_item_quantity = $item['quantity']; 
     $line_item_tax_class = $item['tax_class']; 

     mysqli_stmt_bind_param($stmt, 'isssssssssssssssssssssssssssssssssssssssssssss', $number, $line_item_id, $line_item_sub, ...); 
    } 
}