PHP：轉換MySQL代碼，以便它可以與innodb一起使用？

我已經從myisam遷移到innodb，我不得不從表中刪除全文索引。現在我的腳本的某些部分不起作用，我如何轉換下面的代碼，以便它將與innodb一起使用？PHP：轉換MySQL代碼，以便它可以與innodb一起使用？

$posts_fields = "SELECT SQL_CALC_FOUND_ROWS id, autor, " . PREFIX . "_post.date AS newsdate, " . PREFIX ."_post.date AS date, short_story AS story, " . PREFIX . "_post.xfields AS xfields, title, descr, keywords, category, alt_name,comm_num AS comm_in_news, allow_comm, rating, news_read, flag, editdate, editor, reason, view_edit, tags, '' AS output_comms"; 
$posts_from = "FROM " . PREFIX . "_post"; 
$sql_find = "$sql_fields $posts_from $where";

來源

2012-07-10 Crazy_Bash

什麼不工作了？如果你正在使用'MATCH（..）AGAINST（..）'，那麼問題很可能出現在'$ where'中。 – 2012-07-10 14:48:11

MySQL 5.6支持InnoDB表上的FULLTEXT索引：http：//dev.mysql.com/tech-resources/articles/mysql56-labs-july2011.html。這就是說，你的PHP沒用 - 告訴我們生成的查詢字符串是什麼樣的。 – 2012-07-10 14:49:17

所有代碼都是從表中選擇一個字段列表。沒有代碼會依賴於存儲引擎，也沒有代碼依賴於索引，FULLTEXT或其他。請在嘗試運行查詢時顯示您收到的錯誤消息。 – DaveRandom 2012-07-10 14:49:37

$posts_fields = "SELECT SQL_CALC_FOUND_ROWS id, autor, " . PREFIX . "_post.date AS newsdate, " . PREFIX ."_post.date AS date, short_story AS story, " . PREFIX . "_post.xfields AS xfields, title, descr, keywords, category, alt_name,comm_num AS comm_in_news, allow_comm, rating, news_read, flag, editdate, editor, reason, view_edit, tags, '' AS output_comms"; 
$posts_from = "FROM " . PREFIX . "_post"; 
$sql_find = "$sql_fields $posts_from $where";

應改爲

$posts_fields = "SELECT SQL_CALC_FOUND_ROWS id, autor, " . PREFIX . "_post.date AS newsdate, " . PREFIX ."_post.date AS date, short_story AS story, " . PREFIX . "_post.xfields AS xfields, title, descr, keywords, category, alt_name,comm_num AS comm_in_news, allow_comm, rating, news_read, flag, editdate, editor, reason, view_edit, tags, '' AS output_comms"; 
$posts_from = "FROM " . PREFIX . "_post"; 
$sql_find = "$post_fields $posts_from $where";

，並仔細檢查您的where條件

來源

2012-07-10 15:00:05 satdev86

nope沒有工作 – 2012-07-10 19:09:45

PHP：轉換MySQL代碼，以便它可以與innodb一起使用？

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