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我想將座標x和y插入到二維數組中並打印出來。對於要求輸入的給定代碼示例,它不會執行一次,而是執行兩次,然後接受該值。如果這些值實際上是存儲在每個數組中或者只是一個,我不會。是否可以獨立於矩陣顯示輸出?我aprecciate任何幫助或更正!祝福你。 下面的代碼:如何顯示二維數組中的值?
代碼
import java.util.Scanner;
public class MummyMadness {
public static void main(String []args){
int [][] desert = new int [1][1];
int x =0;
int y =0;
int mummies[] = new int [1];
int Mlimit = 100000;
coordinates(desert,mummies,x,y);
}
public static int[] inputmummy(int mummies[], int Mlimit){
int i;
Scanner input = new Scanner(System.in);
System.out.println("How many mummies you want?");
System.out.println("Note that the limit of mummies is 100k");
i = input.nextInt();
if(mummies[i] > Mlimit)
{
System.out.println("You exceeded from the mummies!");
}
return mummies;
}
public static int[][] coordinates(int desert[][],int mummies[], int x, int y){
//Idea use length of mummies for coordinates but if you take out desert i doesnt work
System.out.println("Enter mummy coordinates");
for(int i = 0; i < desert.length; i++){
System.out.println("Enter x:");
Scanner input = new Scanner(System.in);
if(input.nextInt() > desert.length)
{
System.out.println("Error x exceeded desert length");
break;
}
desert[i][0] = input.nextInt();
System.out.println("Mummy location x: " + desert[i][0]);
for(int j = 0; j < mummies.length; j++){
System.out.println("Enter y:");
Scanner input2 = new Scanner(System.in);
if(input.nextInt() > desert[0].length)
{
System.out.println("Error y exceeded desert length");
break;
}
desert[0][j] = input2.nextInt();
System.out.println("Mummy location y: " + desert[0][j]);
System.out.println(desert[i][j])
}
}
return desert;
}
}
工作正常!謝謝你,謝拉。這意味着無論何時我想插入輸入,我都不應該使用input.next,因爲它會自動請求輸入。謝謝。另外在代碼的底部,當我在做第二個輸入時,我對掃描器input2做了一個新的引用,並使用它,使y的值存儲在x中。 –