我試圖製作複製目錄的子項目的程序,但我無法標記所有特定名稱,因爲它們在每個文件夾中都有所不同。這是我的代碼,但是如果源是「C:\ src」,輸出是「C:\ dst」,它會創建文件夾「C:\ dst \ src(children files)」,但我想make「C:\ dst(子文件)」。誰能幫忙?在Java中將源文件的子文件複製到目的地
public static void copy(File source, File destination) throws IOException {
if (source == null) {
throw new NullPointerException("Null Source");
}
if (destination == null) {
throw new NullPointerException("Null Destination");
}
if (source.isDirectory()) {
copyDirectory(source, destination);
} else {
copyFile(source, destination);
}
}
//converts to location
public static void copyDirectory(File source, File destination) throws IOException {
copyDirectory(source, destination, null);
}
public static void copyDirectory(File source, File destination, FileFilter filter) throws IOException {
File nextDirectory = new File(destination, source.getName());
if (!nextDirectory.exists() && !nextDirectory.mkdirs()) {// create the directory if necessary...
Object[] filler = {nextDirectory.getAbsolutePath()};
String message = "Dir Copy Failed";
throw new IOException(message);
}
File[] files = source.listFiles();
for (int n = 0; n < files.length; ++n) {// and then all the items below the directory...
if (filter == null || filter.accept(files[n])) {
if (files[n].isDirectory()) {
copyDirectory(files[n], nextDirectory, filter);
} else {
copyFile(files[n], nextDirectory);
}
}
}
}
public static void copyFile(File source, File destination) throws IOException {
// what we really want to do is create a file with the same name in that dir
if (destination.isDirectory()) {
destination = new File(destination, source.getName());
}
FileInputStream input = new FileInputStream(source);
copyFile(input, destination);
}
public static void copyFile(InputStream input, File destination) throws IOException {
OutputStream output = null;
try {
output = new FileOutputStream(destination);
byte[] buffer = new byte[1024];
int bytesRead = input.read(buffer);
while (bytesRead >= 0) {
output.write(buffer, 0, bytesRead);
bytesRead = input.read(buffer);
}
} catch (Exception e) {
//
} finally {
input.close();
output.close();
}
input = null;
output = null;
}
如果你這樣做不僅僅是腦部運動,我應該警告你,你可以在命令行中的一行。 'cp -r src/*。/ dst' – thatidiotguy