設置函數調用python中的raw_input

Question

我該如何完成這項工作？我正在嘗試設置一個全局函數，以便稍後可以將其稱爲原始輸入，而不是在需要時調用原始輸入。

我認爲我的精髓在於我需要的程度，但我很難理解如何格式化，或者甚至可能。

預先感謝您。

def choice_1(): 
     choice_1 == raw_input("> ") 
    def choice_1a():  
     choice_1a = raw_input("> ") 
    def choice_1b():  
     choice_1b = raw_input("> ") 

編輯：我不認爲我是在我的問題的目的很清楚。這裏是我正在處理的代碼的更新，也許這將清除一切。

print "You've arrived at your desk" 


def choice_1(one): 
    choice_1a = raw_input("< ") 
def choice_1a():  
    choice_1a = raw_input("> ") 
def choice_1b():  
    choice_1b = raw_input("> ") 

#Choice_1 
print "What do you want to do?" 
print "We can \n1. Read\n2. Draw\n3. Work on homework" 
print choice_1 
#choice 1 branch 1 
if choice_1 == "1": 
    print "What book should we read today?" 
    print "We can read\n1. Tom Sawyer\n2. Quantum Physics \n3. Ray Bradbury" 
    print choice_1a 
    if choice_1a == "1": 
     print "Great choice!" 
    if choice_1a == "2": 
     print "Heavy stuff there." 
    if choice_1a == "3": 
     print "Entertaining author, that one there!" 
    else: 
     print "Let's go to the library, maybe they'll have that one." 
#choice 1 branch 2 
if choice_1 == "2": 
    print "What would you like to draw?" 
    print "We can draw a\n1. Tiger\n2. Fish\n3. Bear " 
    print choice_1b 
    if choice_1b == "1": 
     print "You drew a Tiger!" 
    if choice_1b == "2": 
     print "You drew a Fish!" 
    if choice_1b == "3": 
     print "You drew a Bear!" 
    else: 
     print "Time for some improvisation." 

#choice 1 branch 3 
if choice_1 == "3": 
    print "" 

這是否清楚了一些混淆？

Answer 1

這會做你想做的。作爲@SethMMorton注意到，您曾經在return

def choice(): 
    return raw_input('> ‘) 

順便說錯過了，這不是一個很好的事情，因爲，給別人讀你的代碼，它不會立即清楚什麼choice是這樣做。

我這樣做：

print 'Your name is :' + choice() 

和它的工作如預期。

編輯：你應該讓你如果這樣的語句：

if choice() == "1"：

Answer 2

def multiplier(x, y): 
    ans = x * y 
    print ans 

這將是一個功能的使用，當準備使用它，你會 這樣稱呼它

multiplier(5, 10) 
     50