從父母刪除孩子的春季啓動問題

Question

我希望得到你們所有人的建議。我很享受Spring引導框架，但是我遇到了使用JPA和Hibernate刪除祖父母的問題。

我有一個相當複雜的設置程序提醒你，所以我很快就會解釋佈局：

孩子（網站）可以有：

• 1產品（父）
• 1提供
• 許多價格（兒童）

父（產品）可得：

• 許多網站（兒童）

供應商可以有：

• 許多網站

的價格可以有：

• 1網站（父）

所以它就像一個祖父母 - >父母 - >孩子的關係。我的問題是，如何在不刪除祖父母和提供者的情況下刪除父母？

這裏是我的客艙佈局：

祖父母：

@Entity 
@NoArgsConstructor(force = true) 
@RequiredArgsConstructor 
@Table(name = "product") 
@Getter 
@Setter 
public class Product { 

    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    private long id; 

    @OneToMany(mappedBy = "product", cascade = CascadeType.ALL, fetch = FetchType.EAGER) 
    private List<Website> website; 

} 

家長：

@Entity 
@NoArgsConstructor(force = true) 
@RequiredArgsConstructor 
@Table(name = "website") 
@Getter 
@Setter 
public class Website { 
    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    private long id; 

    @ManyToOne 
    @JoinColumn(name = "product_id") 
    private @NotNull Product product; 

    @ManyToOne 
    @JoinColumn(name = "provider_id") 
    private @NotNull Provider provider; 

    @OneToMany(mappedBy = "website", cascade = CascadeType.ALL, orphanRemoval = true, fetch = FetchType.EAGER) 
    private List<Price> priceList; 
} 

提供者：

@Entity 
@NoArgsConstructor(force = true) 
@RequiredArgsConstructor 
@Table(name = "provider") 
@Getter 
@Setter 
public class Provider { 

    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    private long id; 

    @JsonIgnore 
    @OneToMany(mappedBy = "provider", fetch = FetchType.EAGER) 
    private List<Website> website; 
} 

兒童：

@Entity 
@NoArgsConstructor(force = true) 
@RequiredArgsConstructor 
@Table(name = "price") 
@Getter 
@Setter 
public class Price { 

    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    private long id; 

    @ManyToOne 
    @JoinColumn(name = "website_id") 
    private Website website; 
} 

控制器：

@Autowired 
private IWebsiteRepository repository; 
@RequestMapping(path = "/admin/delete/{id}", method = RequestMethod.POST) 
public ModelAndView deletePost(@PathVariable("id") long id) { 
    repository.delete(id); 

    return new ModelAndView("redirect:/price/api/website/admin/"); 
} 

資源庫：

public interface IWebsiteRepository extends CrudRepository<Website, Long> { 
    Website findById(long id); 
    List<Website> findAll(); 
} 

刪除是這裏的默認方法爲這個資料庫，但它不會刪除該網站。這裏是會從休眠輸出，當我按下刪除控制端點：

Hibernate: select website0_.id as id1_4_, website0_.date as date2_4_, website0_.product_id as product_4_4_, website0_.provider_id as provider5_4_, website0_.url as url3_4_ from website website0_ 
Hibernate: select product0_.id as id1_2_0_, product0_.activate as activate2_2_0_, product0_.date as date3_2_0_, product0_.name as name4_2_0_, website1_.product_id as product_4_4_1_, website1_.id as id1_4_1_, website1_.id as id1_4_2_, website1_.date as date2_4_2_, website1_.product_id as product_4_4_2_, website1_.provider_id as provider5_4_2_, website1_.url as url3_4_2_, pricelist2_.website_id as website_4_1_3_, pricelist2_.id as id1_1_3_, pricelist2_.id as id1_1_4_, pricelist2_.date as date2_1_4_, pricelist2_.price as price3_1_4_, pricelist2_.website_id as website_4_1_4_, provider3_.id as id1_3_5_, provider3_.colour as colour2_3_5_, provider3_.date as date3_3_5_, provider3_.name as name4_3_5_, provider3_.target_name as target_n5_3_5_ from product product0_ left outer join website website1_ on product0_.id=website1_.product_id left outer join price pricelist2_ on website1_.id=pricelist2_.website_id left outer join provider provider3_ on website1_.provider_id=provider3_.id where product0_.id=? 
Hibernate: select product0_.id as id1_2_0_, product0_.activate as activate2_2_0_, product0_.date as date3_2_0_, product0_.name as name4_2_0_, website1_.product_id as product_4_4_1_, website1_.id as id1_4_1_, website1_.id as id1_4_2_, website1_.date as date2_4_2_, website1_.product_id as product_4_4_2_, website1_.provider_id as provider5_4_2_, website1_.url as url3_4_2_, pricelist2_.website_id as website_4_1_3_, pricelist2_.id as id1_1_3_, pricelist2_.id as id1_1_4_, pricelist2_.date as date2_1_4_, pricelist2_.price as price3_1_4_, pricelist2_.website_id as website_4_1_4_, provider3_.id as id1_3_5_, provider3_.colour as colour2_3_5_, provider3_.date as date3_3_5_, provider3_.name as name4_3_5_, provider3_.target_name as target_n5_3_5_ from product product0_ left outer join website website1_ on product0_.id=website1_.product_id left outer join price pricelist2_ on website1_.id=pricelist2_.website_id left outer join provider provider3_ on website1_.provider_id=provider3_.id where product0_.id=? 
Hibernate: select website0_.provider_id as provider5_4_0_, website0_.id as id1_4_0_, website0_.id as id1_4_1_, website0_.date as date2_4_1_, website0_.product_id as product_4_4_1_, website0_.provider_id as provider5_4_1_, website0_.url as url3_4_1_, product1_.id as id1_2_2_, product1_.activate as activate2_2_2_, product1_.date as date3_2_2_, product1_.name as name4_2_2_ from website website0_ inner join product product1_ on website0_.product_id=product1_.id where website0_.provider_id=? 

我希望這是有道理的

Answer 1

我會說沒有積極的交易，沒有交易JPA不會刪除任何東西。

嘗試添加@Transactional來刪除控制器中的郵件。