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我想要下面的代碼razrada.show();被執行後,我按保存在我的AlertDialog,但它顯示並關閉 這是我的代碼警報對話框在不按下的情況下關閉anything_android
AlertDialog.Builder razradaPlacanja = new AlertDialog.Builder(NoviRacun.this);
razradaPlacanja.setTitle("Način plaćanja");
LayoutInflater inflater = getLayoutInflater();
View vieww = inflater.inflate(R.layout.razrada, null);
razradaPlacanja.setView(vieww);
final EditText gotovinaEdit = (EditText) vieww.findViewById(R.id.gotovinaEdit);
final EditText karticeEdit = (EditText) vieww.findViewById(R.id.karticeEdit);
razradaPlacanja.setPositiveButton("Save",
new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
try {
json.put("TotalCash", gotovinaEdit.getText().toString());
json.put("TotalCreditCards", karticeEdit.getText().toString());
} catch (JSONException e) {
e.printStackTrace();
}
}
});
AlertDialog razrada = razradaPlacanja.create();
razrada.getWindow().setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_VISIBLE);
razrada.show();
//this i want to execute after pressing Save
Racuni racun = getInsertResponse(requestInsert(base64EncodedCredentials, json, httpclient1));
try {
...
我不能把 Racuni racun = getInsertResponse(requestInsert(base64EncodedCredentials,JSON,httpclient1)); 裏面的onClick塊導致然後racun是無法訪問(如果宣佈外,需要是最終的,然後我不能asign值)
謝謝你的任何幫助!
但我將如何獲得變量racun? – sparrkli
你應該在新方法中處理它。你不能這樣做嗎? – Szymon
我只是把整個代碼放在外面的方法中。感謝您的回覆,我會接受答案。 – sparrkli