好吧,我已經GOOGLE和GOOGLE更多一些,我卡住了。我對PHP的想法確實很陌生,但我最終讓自己的表單做了我想做的事,除了當我將它發送給我的電子郵件時,它只顯示了我檢查過的其中一個框。我真的很討厭尋求幫助,但這裏就是這樣。發送查詢從「檢查」的HTML框通過電子郵件發送電子郵件通過PHP
這裏是我的html:
<tr>
<td valign="left"><p>Please check all items needed *</p>
<p class="style2">(Default order will be one of each checked item unless otherwise indicated in the comments section.)</p>
<td valign="top">
<div align="left">
<input type="checkbox" name="supplies[]" value="black_toner" /> Black Toner<br />
<input type="checkbox" name="supplies[]" value="cyan_toner" /> Cyan Toner<br />
<input type="checkbox" name="supplies[]" value="magenta_toner" /> Magenta Toner<br />
<input type="checkbox" name="supplies[]" value="yellow_toner" /> Yellow Toner<br />
<input type="checkbox" name="supplies[]" value="black_drum" /> Black Drum<br />
<input type="checkbox" name="supplies[]" value="cyan_drum" /> Cyan Drum<br />
<input type="checkbox" name="supplies[]" value="magenta_drum" /> Magenta Drum<br />
<input type="checkbox" name="supplies[]" value="yellow_drum" /> Yellow Drum<br />
<input type="checkbox" name="supplies[]" value="waste_toner" /> Waste Toner<br />
<input type="checkbox" name="supplies[]" value="staples" /> Staples<br />
</div>
<td valign="top"> </td>
</tr>
而這就像我說的,我已經嘗試了什麼,我認爲是一切,但顯然事情是錯我的PHP
}
$email_message = "Form details below.\n\n";
function clean_string($string) {
$bad = array("content-type","bcc:","to:","cc:","href");
return str_replace($bad,"",$string);
}
$email_message .= "First Name: ".clean_string($first_name)."\n";
$email_message .= "Last Name: ".clean_string($last_name)."\n";
$email_message .= "Company: ".clean_string($company)."\n";
$email_message .= "Location: ".clean_string($location)."\n";
$email_message .= "Machine Model: ".clean_string($machine_model)."\n";
$email_message .= "Supplies: ".clean_string($supplies)."\n";
$email_message .= "Email: ".clean_string($email)."\n";
$email_message .= "Telephone: ".clean_string($telephone)."\n";
$email_message .= "Comments: ".clean_string($comments)."\n";
// create email headers
$headers = 'From: '.$email_from."\r\n".
'Reply-To: '.$email_from."\r\n" .
'X-Mailer: PHP/' . phpversion();
@mail($email_to, $email_subject, $email_message, $headers);
?>
。我需要添加到我的PHP/HTML或更改從我的複選框,而不是隻有一個?如果有人有任何建議,我將不勝感激。 (請儘可能具體,就像我說的,我是一個新手)謝謝!
$ _ POST [「供應」]是一個數組,你需要它發生內爆驚人 – 2012-07-25 20:54:27