兩列到一個使用備用行

Question

我有這樣的兩列的表：

A 1 
B 2 
C 3 
D 4 
E 5 

等

我想他們到一列，用的交替行每一列的數據新列是這樣的：

A 
1 
B 
2 
C 
3 
D 
4 
E 
5 

等

Answer 1

CREATE TABLE #Table1(Value VARCHAR(10),Id VARCHAR(10)) 

INSERT INTO #Table1(Value ,Id) 
SELECT 'A',1 UNION ALL 
SELECT 'B',2 UNION ALL 
SELECT 'C',3 UNION ALL 
SELECT 'D',4 UNION ALL 
SELECT 'E',5 

;WITH _CTE (Name) AS 
(
SELECT Value [Name] 
FROM #Table1 
UNION ALL 
SELECT Id [Name] 
FROM #Table1 
) 
SELECT * FROM _CTE 

Answer 2

最棘手的部分是在交替行

select col2 
from 
(select col1, 1 as flag, col1 from tab 
    union all 
    select col1, 2,   col2 from tab 
) as dt 
order by col1, flag 

但是，爲什麼你嘗試這樣做，在所有數據？

Answer 3

試試這個：

WITH CTE AS 
(
    SELECT Col1Name Name,(ROW_NUMBER() OVER(ORDER BY(SELECT NULL))) RN 
    FROM TableName 
    UNION 
    SELECT Col2Name Name,(ROW_NUMBER() OVER(ORDER BY(SELECT NULL)))+1 RN 
    FROM TableName 
) 
SELECT Name 
FROM CTE 
ORDER BY RN 

Answer 4

我會用一個UNION ALL但這裏是UNPIVOT選擇：

CREATE TABLE #Table1(letter VARCHAR(10),Id VARCHAR(10)) 

INSERT INTO #Table1(letter ,Id) 
SELECT 'A',1 UNION ALL 
SELECT 'B',2 UNION ALL 
SELECT 'C',3 UNION ALL 
SELECT 'D',4 UNION ALL 
SELECT 'E',5 


SELECT [value] 
FROM #Table1 
UNPIVOT 
(
    [value] FOR [Column] IN ([Id], [letter]) 
) UNPVT 


DROP TABLE #Table1;