我有這個json下面。我試圖使用json_decode獲取值。我得到了一些值，但是我在深度嵌套值方面遇到了問題。這裏是JSON：PHP：嵌套json和值提取

{ 
"startAt": 0, 
"issue": [ 
{ 
    "id": "51526", 
    "fields": { 
     "people": [ 
      { 
       "name": "bob", 
       "emailAddress": "[email protected]", 
       "displayName": "Bob Smith", 
      }, 
      { 
       "name": "john", 
       "emailAddress": "[email protected]", 
       "displayName": "John Smith", 
      } 
     ], 
     "skill": { 
      "name": "artist", 
      "id": "1" 
     } 
    } 
}, 
{ 
    "id": "2005", 
    "fields": { 
     "people": [ 
      { 
       "name": "jake", 
       "emailAddress": "[email protected]", 
       "displayName": "Jake Smith", 
      }, 
      { 
       "name": "frank", 
       "emailAddress": "[email protected]", 
       "displayName": "Frank Smith", 
      } 
     ], 
     "skill": { 
      "name": "writer", 
      "id": "2" 
     } 
    } 
} 
] 

}

我知道我可以通過這樣得到一個值：

foreach ($decoded_array['issue'][0]['fields']['people'] as $person) { 
    echo $person['emailAddress']; 
}

然而，有一個簡單的辦法讓所有的「emailAddresses」鮑勃，約翰，傑克，坦率地說？

謝謝！

來源

2014-04-04 Jason

最簡單的方法實際上只是循環，但首先在$decoded_array['issue']上嵌套循環，然後在['people']上嵌套循環。將你的地址收集到一個輸出數組中。

// Note: this assumes you called json_decode() with the second 
// param TRUE to force an associative array.. 
// $decoded_array = json_decode($input_json, TRUE); 

$addresses = array(); 
foreach ($decoded_array['issue'] as $i) { 
    foreach ($i['fields']['people'] as $person) { 
    // Append the address onto an output array 
    $addresses[] = $person['emailAddress']; 
    } 
} 
// De-dupe them if necessary 
$addresses = array_unique($addresses); 
print_r($addresses); 

// Prints 
Array 
(
    [0] => [email protected] 
    [1] => [email protected] 
    [2] => [email protected] 
    [3] => [email protected] 
)

如果你沒有一定的不同之處在於按鍵被命名爲emailAddress是使用array_walk_recurisve()遍歷數組，尋找該鍵的結構稍微票友方法。這將收集所有密鑰，名爲emailAddress，而不僅僅是['people']子陣列中的那些密鑰。

$addresses = array(); 
// Pass $addresses into the closure by reference so you can write to it 
array_walk_recursive($decoded_array, function($value, $key) use (&$addresses) { 
    // Find *all keys* called emailAddress 
    if ($key == 'emailAddress') { 
    $addresses[] = $value; 
    } 
});

來源

2014-04-04 00:17:38

嘗試：

function people($peopleArray, $searchProperty, $forValueArray){ 
    $fva = array_map('strtolower', $forValuArray); 
    foreach($peopleArray as $v){ 
    $sp = $v[$searchProperty]; $sl = strtolower($sp); 
    if(in_array($sl, $fva)){ 
     $q[] = $sp; 
    } 
    } 
    return isset($q) ? $q : 0; 
} 
if($ans = people($decoded_array, 'emailAddress', array('bob', 'john', 'jake', 'frank'))){ 
    print_r($ans); 
} 
else{ 
    echo 'no results found'; 
}

來源

2014-04-04 00:42:50 PHPglue

腳本：

$json = "......"           //Your json text. 
$decoded_array = json_decode($json)->{'issue'};   //Decode Json string 
foreach($decoded_array as $issue){      //Get all Issues 
    foreach($issue->{'fields'}->{'people'} as $person){ //Get all people 
     echo $person->{'emailAddress'}."<br/>";   //Get person's email 
    } 
}