MySQL查詢，將省略至少和最多次重複的結果

Question

我需要一個MySQL查詢來獲得結果，其中不會有大部分和最少重複的值。

這是什麼意思？

如果MySQL查詢：

SELECT Ocjena,COUNT(*) FROM ocjenjivanje GROUP BY Ocjena; 

回報：

我需要查詢，這將給我的下一個結果：

Ocjena 
1 
3 
5 

感謝

Answer 1

試試這個：

SELECT o.* 
FROM (SELECT Ocjena, COUNT(*) AS c FROM ocjenjivanje GROUP BY Ocjena) AS o 
INNER JOIN (SELECT Min(c) AS l, Max(c) AS h FROM (SELECT Ocjena, COUNT(*) AS c FROM ocjenjivanje GROUP BY Ocjena)) AS m 
ON o.c <> m.l AND o.c <> m.h 
----OR 
--ON o.c NOT IN(m.l, m.h) 

，或者您可以使用此查詢：

SELECT Ocjena, c 
FROM 
(SELECT o.*, @min:=IF(@min > o.c, o.c, @min) AS l, @max:=IF(@max < o.c, o.c, @max) AS h 
    FROM (SELECT Ocjena, COUNT(*) AS c FROM ocjenjivanje GROUP BY Ocjena) AS o 
    , (select @max:=0, @min:=32000) AS m) AS x 
WHERE c NOT IN(l, h) 

Answer 2

這裏是我的解決方案。

我不知道我可以更好地看起來更專業或更快，或類似的東西。

SELECT * FROM  `Ocjenjivanje` WHERE Ocjena != ( SELECT Ocjena 
FROM  `Ocjenjivanje` 
GROUP BY `Ocjena` 
ORDER BY `Ocjena` DESC 
LIMIT 1) AND OCjena != (SELECT Ocjena 
FROM  `Ocjenjivanje` 
GROUP BY `Ocjena` 
ORDER BY `Ocjena` ASC 
LIMIT 1) 
GROUP BY `Ocjena` 

Answer 3

你可以得到這樣的查詢張貼在你的答案（但不返回預期的問題行）使用此查詢之一：

SELECT o.* 
FROM (SELECT Ocjena, COUNT(*) AS c FROM ocjenjivanje GROUP BY Ocjena) AS o 
INNER JOIN (SELECT Min(Ocjena) AS l, Max(Ocjena) AS h FROM ocjenjivanje) AS m 
ON o.Ocjena <> m.l AND o.Ocjena <> m.h 

SELECT Ocjena, COUNT(*) AS c 
FROM ocjenjivanje AS o 
WHERE o.Ocjena <> (SELECT Min(Ocjena) FROM ocjenjivanje) 
AND o.Ocjena <> (SELECT Max(Ocjena) FROM ocjenjivanje) 
GROUP BY Ocjena 

SELECT Ocjena, COUNT(*) AS c 
FROM ocjenjivanje AS o 
WHERE o.Ocjena NOT IN (SELECT Min(Ocjena) FROM ocjenjivanje UNION SELECT Max(Ocjena) FROM ocjenjivanje) 
GROUP BY Ocjena