檢測Webview錯誤並顯示消息

我想在加載webview頁面時發生錯誤消息（無連接）。這是我到目前爲止，沒有錯誤處理代碼：檢測Webview錯誤並顯示消息

public class TrackerPage extends Activity { 

    // @Override 
    private WebView webview; 
    private ProgressDialog progressDialog; 

    private boolean error; 

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 

     // Get rid of the android title bar 
     requestWindowFeature(Window.FEATURE_NO_TITLE); 

     // Set the XML layout 
     setContentView(R.layout.tracker_page); 

     // Bundle objectbundle = this.getIntent().getExtras(); 
     webview = (WebView) findViewById(R.id.tracker); 

     final Activity activity = this; 

     // Enable JavaScript and lets the browser go back 
     webview.getSettings().setJavaScriptEnabled(true); 
     webview.canGoBack(); 

     webview.setWebViewClient(new WebViewClient() { 
      public boolean shouldOverrideUrlLoading(WebView view, String url) { 
       view.loadUrl(url); 
       return true; 
      } 

      public void onLoadResource(WebView view, String url) { 
       // Check to see if there is a progress dialog 
       if (progressDialog == null) { 
        // If no progress dialog, make one and set message 
        progressDialog = new ProgressDialog(activity); 
        progressDialog.setMessage("Loading please wait..."); 
        progressDialog.show(); 

        // Hide the webview while loading 
        webview.setEnabled(false); 
       } 
      } 

      public void onPageFinished(WebView view, String url) { 
       // Page is done loading; 
       // hide the progress dialog and show the webview 
       if (progressDialog.isShowing()) { 
        progressDialog.dismiss(); 
        progressDialog = null; 
        webview.setEnabled(true); 
       } 
      } 

     }); 

     // The URL that webview is loading 
     webview.loadUrl("http://url.org/"); 
    } 
}

我該怎麼做？

來源

2011-06-17 HighLife

以上所有答案均已棄用。您應使用此代碼後頁面完成

@Override 
    public void onReceivedError(WebView view, WebResourceRequest request, WebResourceError error){ 
      //Your code to do 
     Toast.makeText(getActivity(), "Your Internet Connection May not be active Or " + error , Toast.LENGTH_LONG).show(); 
    }

來源

2016-05-10 17:50:26

如果您的項目的目標API級別<23，如何使用上述內容？ – Michael

@Michael，還有另一種API級別1引入的不同參數的方法 - onReceivedError（WebView，int，String，String） – cdeange

如果沒有互聯網，我看到的只是「找不到網頁」，並且沒有任何回調叫做。怎麼來的？另外，使用onReceivedError的新API會更好嗎？根據文檔，它被稱爲頁面上的每個組件。如何在整個頁面中檢查它？ –

你大部分的方式......只是實施onReceivedError並處理你想要的錯誤。

來源

2011-06-17 22:23:17 kabuko

執行此操作但不捕獲JavaScript錯誤只有連接錯誤等。 – Codebeat

對於javascript錯誤，請設置WebChromeClient重寫onConsoleMessage（）。 – Alex

添加此之後onpagefinished：

public void onReceivedError(WebView view, int errorCod,String description, String failingUrl) { 
      Toast.makeText(Webform.this, "Your Internet Connection May not be active Or " + description , Toast.LENGTH_LONG).show(); 
     }

不要忘了進口android.widget.Toast;

來源

2011-12-29 21:12:48 Yahyaotaif

更新的答案，每個API 23棉花糖

WebViewClient錯誤處理

/* 
    * Added in API level 23 replacing :- 
    * 
    * onReceivedError(WebView view, int errorCode, String description, String failingUrl) 
    */ 
    @Override 
    public void onReceivedError(WebView view, WebResourceRequest request, 
      WebResourceError error) { 

     Toast.makeText(getActivity(), 
       "WebView Error" + error.getDescription(), 
       Toast.LENGTH_SHORT).show(); 

     super.onReceivedError(view, request, error); 

    } 

    /* 
     Added in API level 23 
    */ 
    @Override 
    public void onReceivedHttpError(WebView view, 
      WebResourceRequest request, WebResourceResponse errorResponse) { 

     Toast.makeText(getActivity(), 
       "WebView Error" + errorResponse.getReasonPhrase(), 
       Toast.LENGTH_SHORT).show(); 


     super.onReceivedHttpError(view, request, errorResponse); 
    }

網絡錯誤處理

 webView.loadUrl(urlToLoad); 

     if (!isConnected(getActivity())) { 
      Toast.makeText(getActivity(), "You are offline ", Toast.LENGTH_SHORT).show(); 

     } 

    /** 
    * Check if there is any connectivity 
    * 
    * @param context 
    * @return is Device Connected 
    */ 
    public static boolean isConnected(Context context) { 

     ConnectivityManager cm = (ConnectivityManager) context 
       .getSystemService(Context.CONNECTIVITY_SERVICE); 

     if (null != cm) { 
      NetworkInfo info = cm.getActiveNetworkInfo(); 

      return (info != null && info.isConnected()); 
     } 
     return false; 
    }

來源

2016-05-28 09:43:14

public class WebClient extends WebViewClient { 

    @Override 
    @TargetApi(Build.VERSION_CODES.M) 
    public void onReceivedError(WebView view, WebResourceRequest request, WebResourceError error) { 
     super.onReceivedError(view, request, error); 
     final Uri uri = request.getUrl(); 
     handleError(view, error.getErrorCode(), error.getDescription().toString(), uri); 
    } 

    @SuppressWarnings("deprecation") 
    public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) { 
     super.onReceivedError(view, errorCode, description, failingUrl); 
     final Uri uri = Uri.parse(failingUrl); 
     handleError(view, errorCode, description, uri); 
    } 

    private void handleError(WebView view, int errorCode, String description, final Uri uri) { 
     final String host = uri.getHost();// e.g. "google.com" 
     final String scheme = uri.getScheme();// e.g. "https" 
     // TODO: logic 
    } 
}

來源

2017-04-02 09:29:09

檢測Webview錯誤並顯示消息

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