<?php
session_start();
include_once 'db.login.php';
if (isset($_SESSION['users']) != "") {
header("Location: profile.php");
}
if (isset($_POST['btn-login'])) {
$username = mysqli_real_escape_string($con, $_POST['username']);
$upass = mysqli_real_escape_string($con, $_POST['password']);
$res = mysqli_query($con, "SELECT * FROM users WHERE username='$username'");
$row = mysqli_fetch_array($res);
if ($row['password'] == md5($upass)) {
$_SESSION['users'] = $row['id'];
header("Location: profile.php");
} else {
$err = "<p style='color: red'>Wrong Username or Password</p>";
?>
<?php
}
}
?>
方法,我想,但它似乎並沒有顯示任何呼應現有會話的用戶名PHP
<?= $_SESSION['username'] ?>">
我基本上看呼應登錄會話的用戶名
你是否確實存在?試試'var_dump($ _ SESSION ['username'])''。 – poletaew
你打算在哪裏打印? –
'if(isset($ _ SESSION ['users'])!=「」)'是一種誤報方法。 –