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下面是我的代碼,我希望上傳圖像在一個特定的行,所以我想使用where關鍵字在SQL查詢,但是當我在下面的代碼中使用SQL查詢where關鍵字它不工作。請幫助我如何上傳圖像在mysql中使用php與哪裏conditon
<?php
error_reporting(E_ALL);
ini_set('display_errors',1);
if($_SERVER['REQUEST_METHOD']=='POST'){
$image=$_FILES['imageup']['tmp_name'];
$img=file_get_contents($image);
$con=mysqli_connect('localhost','aish','aish123','photo') or die('Unable To connect');
$sql="insert into image (img) values(?)";
$stmt=mysqli_prepare($con,$sql);
mysqli_stmt_bind_param($stmt,"s",$img);
mysqli_stmt_execute($stmt);
$check=mysqli_stmt_affected_rows($stmt);
if($check==1){
$msg = 'Successfullly UPloaded';
}else{
$msg = 'Could not upload';
}
mysqli_close($con);
}
?>
感謝它正在工作 –