Python調用父方法多繼承

Question

所以，我有這樣的情況。

class A(object): 
    def foo(self, call_from): 
     print "foo from A, call from %s" % call_from 


class B(object): 
    def foo(self, call_from): 
     print "foo from B, call from %s" % call_from 


class C(object): 
    def foo(self, call_from): 
     print "foo from C, call from %s" % call_from 


class D(A, B, C): 
    def foo(self): 
     print "foo from D" 
     super(D, self).foo("D") 

d = D() 
d.foo() 

代碼的結果是

foo from D 
foo from A, call from D 

我想打電話給所有的父類的方法，在這種情況下，FOO的方法，從D課，而不會在諸如A父類使用超。我只想打電話給D這個班。 A,B和C類就像mixin類，我想調用D的所有foo方法。我怎樣才能做到這一點？

Answer 1

您可以使用__bases__這樣

class D(A, B, C): 
    def foo(self): 
     print "foo from D" 
     for cls in D.__bases__: 
      cls().foo("D") 

隨着這一變化，輸出將是

foo from D 
foo from A, call from D 
foo from B, call from D 
foo from C, call from D 

Answer 2

添加super()呼叫的其他類以及除了C。由於D的MRO是

>>> D.__mro__ 
(<class '__main__.D'>, <class '__main__.A'>, <class '__main__.B'>, <class '__main__.C'>, <type 'object'>) 

你不需要超級呼叫C。

代碼：

class A(object): 
    def foo(self, call_from): 
     print "foo from A, call from %s" % call_from 
     super(A,self).foo('A') 

class B(object): 
    def foo(self, call_from): 
     print "foo from B, call from %s" % call_from 
     super(B, self).foo('B') 


class C(object): 
    def foo(self, call_from): 
     print "foo from C, call from %s" % call_from 

class D(A, B, C): 
    def foo(self): 
     print "foo from D" 
     super(D, self).foo("D") 

d = D() 
d.foo() 

輸出：

foo from D 
foo from A, call from D 
foo from B, call from A 
foo from C, call from B