如何使用PowerShell爲多個子目錄創建目錄連接？

Question

有很多子文件夾，並且只能爲二階子文件夾創建目錄連接。

當前文件夾結構的某些部分如下所示

C:\MainFolder>tree 
Folder PATH listing for volume C System 
C:. 
├───1stSub-FolderA 
│ ├───2ndSub-FolderA 
│ └───2ndSub-FolderB 
└───1stSub-FolderB 
    ├───2ndSub-FolderA 
    └───2ndSub-FolderB 

D:\MainFolder-Copy>tree 
Folder PATH listing for volume Dosya 
D:. 
├───1stSub-FolderA 
└───1stSub-FolderB 

手冊編碼爲每個文件夾：

C:\>mklink /j D:\MainFolder-Copy\1stSub-FolderA\2ndSub-FolderA C:\MainFolder\1stSub-FolderA\2ndSub-FolderA 
Junction created for D:\MainFolder-Copy\1stSub-FolderA\2ndSub-FolderA <<===>> C:\MainFolder\1stSub-FolderA\2ndSub-FolderA 

C:\>mklink /j D:\MainFolder-Copy\1stSub-FolderA\2ndSub-FolderB C:\MainFolder\1stSub-FolderA\2ndSub-FolderB 
Junction created for D:\MainFolder-Copy\1stSub-FolderA\2ndSub-FolderB <<===>> C:\MainFolder\1stSub-FolderA\2ndSub-FolderB 

C:\>mklink /j D:\MainFolder-Copy\1stSub-FolderB\2ndSub-FolderA C:\MainFolder\1stSub-FolderB\2ndSub-FolderA 
Junction created for D:\MainFolder-Copy\1stSub-FolderB\2ndSub-FolderA <<===>> C:\MainFolder\1stSub-FolderB\2ndSub-FolderA 

C:\>mklink /j D:\MainFolder-Copy\1stSub-FolderB\2ndSub-FolderB C:\MainFolder\1stSub-FolderB\2ndSub-FolderB 
Junction created for D:\MainFolder-Copy\1stSub-FolderB\2ndSub-FolderB <<===>> C:\MainFolder\1stSub-FolderB\2ndSub-FolderB 

結果：

C:\MainFolder>tree 
Folder PATH listing for volume C System 
C:. 
├───1stSub-FolderA 
│ ├───2ndSub-FolderA 
│ └───2ndSub-FolderB 
└───1stSub-FolderB 
    ├───2ndSub-FolderA 
    └───2ndSub-FolderB 

D:\MainFolder-Copy>tree 
Folder PATH listing for volume Dosya 
D:. 
├───1stSub-FolderA 
│ ├───2ndSub-FolderA 
│ └───2ndSub-FolderB 
└───1stSub-FolderB 
    ├───2ndSub-FolderA 
    └───2ndSub-FolderB 

如何使它對一切都只是第二訂購子文件夾幾個命令，而不是手動爲每個文件夾寫代碼？命令不應該爲第1，第3，第4，第5 ...個子文件夾創建目錄結點。

Answer 1

試試這個：

Get-ChildItem D:\MainFolder-Copy -Directory | 
    Foreach {Get-ChildItem (Join-Path C:\MainFolder $_.Name) -Directory} | 
    Foreach {cmd /c mklink /j ($_.FullName -replace 'C:\\MainFolder','D:\MainFolder-Copy') $_.FullName}