導出嵌套從Postgres數據庫到Excel表格文件 - 使用PHP

Question

我在數據庫（研究，站點，實驗室和研究人員）4桌。它們涉及以下方式：

1研究 1.1網站 1.1.1實驗室 1.1.2調查

我試圖從這些表中的數據導出到Excel文件，按照上述的結構。但它只是循環並打印每個級別第一個項目的信息。我怎樣才能讓它打印所有項目？

這是我的代碼：

<?php 

header("Content-Type: application/xls");  
header("Content-Disposition: attachment; filename=filename.xls"); 
header("Pragma: no-cache"); 
header("Expires: 0"); 

include_once("C:/webroot/connect.php"); 


//loop the query data to the table in same order as the headers 
$sql_data = "select agent, study, ind_no, sponsor, status from dw_regtrack.qlstudies st left join dw_regtrack.user_studies us ON st.study=us.study_name where user_name='gsamara'"; 
$sql_data2="select study, amtrackid, name, pi, status, irbappcr, ohrp, ib, prot, ic, global1572, 1572, ibc, obarac, dsa FROM dw_regtrack.qlstudysites2"; 
$sql_data3="select amtrackid, labid, name, cap, clia, lnv FROM dw_regtrack.qlstudysitelabs"; 
$sql_data4="select amtrackid, personid, name, cv, ml, fd, hspt, dot, pisort from dw_regtrack.qlstudysiteinvests2"; 

$result=pg_query($sql_data); 
$result2=pg_query($sql_data2); 
$result3=pg_query($sql_data3); 
$result4=pg_query($sql_data4); 


while ($row = pg_fetch_array($result, NULL, PGSQL_ASSOC)){ 
    echo implode("\t", array('Agent', 'Study', 'IND No', 'IND Sponsor', 'Current Status'))."\r\n"; 
    echo implode("\t", array($row['agent'], $row['study'], $row['ind_no'],$row['sponsor'], $row['status'])) . "\r\n"; 

    while ($row2=pg_fetch_array($result2, NULL, PGSQL_ASSOC)) 
    { 

     if ($row['study']==$row2['study']){ 
      echo implode("\t", array('','Site', 'PI', 'Status'))."\r\n";   
      echo implode("\t", array('',$row2['name'], $row2['pi'], $row2['status']))."\r\n"; 
     } 

     //foreach 

     while ($row3=pg_fetch_array($result3, NULL, PGSQL_ASSOC)){ 
      if ($row2['amtrackid']==$row3['amtrackid']){ 
       echo implode("\t", array('','','Lab', 'CAP', 'CLIA', 'LNV'))."\r\n"; 
       echo implode("\t", array('','',$row3['name'], $row3['cap'], $row4['clia'],$row4['lnv']))."\r\n"; 
      } 
     } 
     while ($row4=pg_fetch_array($result4, NULL, PGSQL_ASSOC)){ 
      if ($row2['amtrackid']==$row4['amtrackid']){ 
       echo implode("\t", array('','','Investigator', 'CV', 'ML', 'FD'))."\r\n"; 
       echo implode("\t", array('','',$row4['name'], $row4['cv'], $row4['ml'],$row4['fd']))."\r\n"; 
      } 
     } 
    } 
} 


?> 

但是這個代碼是出口數據是這樣的： [！[在這裏輸入的形象描述] [1] [1]

網站行應該是第二級，然後實驗室和調查人員在第三個層次。它應該通過每個代理研究循環，找到通過每個站點相應的站點，然後循環，並發現它的實驗室和研究人員。此外，即使壽它正確打印所有研究代理，它只是遍歷第一項研究劑，它也導出所有數據的其他代理。

任何人都可以幫助我嗎？

謝謝。

Answer 1

問題解決了。這是工作代碼。

<?php 

header("Content-Type: application/xls");  
header("Content-Disposition: attachment; filename=filename.xls"); 
header("Pragma: no-cache"); 
header("Expires: 0"); 

include_once("C:/webroot/connect.php"); 

//loop the query data to the table in same order as the headers 
$sql_data = "SELECT agent, study, ind_no, sponsor, status 
      FROM dw_regtrack.qlstudies st 
      LEFT JOIN dw_regtrack.user_studies us ON st.study=us.study_name 
      WHERE user_name='gsamara'"; 

$sql_data2="SELECT study, amtrackid, name, pi, status, irbappcr, ohrp, ib, prot, ic, global1572, 1572, ibc, obarac, dsa 
      FROM dw_regtrack.qlstudysites2"; 

$sql_data3="SELECT amtrackid, labid, name, cap, clia, lnv 
      FROM dw_regtrack.qlstudysitelabs"; 

$sql_data4="SELECT amtrackid, personid, name, cv, ml, fd, hspt, dot, pisort 
      FROM dw_regtrack.qlstudysiteinvests2"; 

$result=pg_query($sql_data); 

while ($row = pg_fetch_array($result, NULL, PGSQL_ASSOC)){ 
    echo implode("\t", array('Agent', 'Study', 'IND No', 'IND Sponsor', 'Current Status'))."\r\n"; 
    echo implode("\t", array($row['agent'], $row['study'], $row['ind_no'],$row['sponsor'], $row['status'])) . "\r\n"; 

    $result2=pg_query($sql_data2." WHERE study = '".$row['study']."'"); 
    while ($row2=pg_fetch_array($result2, NULL, PGSQL_ASSOC)) 
    { 
     echo implode("\t", array('','Site', 'PI', 'Status'))."\r\n"; 
     echo implode("\t", array('',$row2['name'], $row2['pi'], $row2['status']))."\r\n"; 

     $result3=pg_query($sql_data3." WHERE amtrackid= '".$row2['amtrackid']."'");  
     while ($row3=pg_fetch_array($result3, NULL, PGSQL_ASSOC)){ 
      echo implode("\t", array('','','Lab', 'CAP', 'CLIA', 'LNV'))."\r\n"; 
      echo implode("\t", array('','',$row3['name'], $row3['cap'], $row4['clia'],$row4['lnv']))."\r\n"; 
     } 

     $result4=pg_query($sql_data4." WHERE amtrackid= '".$row2['amtrackid']."'"); 
     while ($row4=pg_fetch_array($result4, NULL, PGSQL_ASSOC)){ 
      echo implode("\t", array('','','Investigator', 'CV', 'ML', 'FD'))."\r\n"; 
      echo implode("\t", array('','',$row4['name'], $row4['cv'], $row4['ml'],$row4['fd']))."\r\n"; 
     } 
    } 
} 

?>