我假設問題更多的是能夠區分磁盤上的排序文件,而不是知道有關文件名本身的任何特定信息。
如果那的情況下,你正在尋找的是什麼東西,是足夠聰明採取類似的列表:
- /path/to/file_1.png
- /路徑/到/ file_2.png
- /path/to/file_3.png
- ...
- /path/to/file_10.png
- /path/to/image_1.png
- /path/to/image_2.png
- ...
- /path/to/image_10.png
,並得到一個結果說 - 我有文件的2個序列:/路徑/到/file_#.png和/path/to/image_#.png你需要2遍 - 第一遍以確定文件的有效表達式,第二遍以找出所有其他文件滿足該要求。
你還需要知道,如果你要支持間隙(是按順序排列是必需的)
- /path/to/file_1.png
- /路徑/到/ file_2巴紐
- /path/to/file_3.png
- /path/to/file_5.png
- /path/to/file_6.png
- /path/to/file_7.png
這是1個序列(/path/to/file_#.png)或2個序列(/path/to/file_1-3.png,/path/to/file_5-7.png)
另外 - 你想如何處理序列中的數字文件?
- /path/to/file2_1.png
- /path/to/file2_2.png
- /path/to/file2_3.png
等
隨着該記住,這是我將如何實現它:
import os.path
import projex.sorting
import re
def find_sequences(filenames):
"""
Parse a list of filenames into a dictionary of sequences. Filenames not
part of a sequence are returned in the None key
:param filenames | [<str>, ..]
:return {<str> sequence: [<str> filename, ..], ..}
"""
local_filenames = filenames[:]
sequence_patterns = {}
sequences = {None: []}
# sort the files (by natural order) so we always generate a pattern
# based on the first potential file in a sequence
local_filenames.sort(projex.sorting.natural)
# create the expression to determine if a sequence is possible
# we are going to assume that its always going to be the
# last set of digits that makes a sequence, i.e.
#
# test2_1.png
# test2_2.png
#
# test2 will be treated as part of the name
#
# test1.png
# test2.png
#
# whereas here the 1 and 2 are part of the sequence
#
# more advanced expressions would be needed to support
#
# test_01_2.png
# test_02_2.png
# test_03_2.png
pattern_expr = re.compile('^(.*)(\d+)([^\d]*)$')
# process the inputed files for sequences
for filename in filenames:
# first, check to see if this filename matches a sequence
found = False
for key, pattern in sequence_patterns.items():
match = pattern.match(filename)
if (not match):
continue
sequences[key].append(filename)
found = True
break
# if we've already been matched, then continue on
if (found):
continue
# next, see if this filename should start a new sequence
basename = os.path.basename(filename)
pattern_match = pattern_expr.match(basename)
if (pattern_match):
opts = (pattern_match.group(1), pattern_match.group(3))
key = '%s#%s' % opts
# create a new pattern based on the filename
sequence_pattern = re.compile('^%s\d+%s$' % opts)
sequence_patterns[key] = sequence_pattern
sequences[key] = [filename]
continue
# otherwise, add it to the list of non-sequences
sequences[None].append(filename)
# now that we have grouped everything, we'll merge back filenames
# that were potential sequences, but only contain a single file to the
# non-sequential list
for key, filenames in sequences.items():
if (key is None or len(filenames) > 1):
continue
sequences.pop(key)
sequences[None] += filenames
return sequences
而且一個例子Ë用法:
>>> test = ['test1.png','test2.png','test3.png','test4.png','test2_1.png','test2_2.png','test2_3.png','test2_4.png']
>>> results = find_sequences(test)
>>> results.keys()
[None, 'test#.png', 'test2_#.png']
有一種方法在那裏,是指天然排序,這是一個單獨的主題。我只是使用我的projex庫中的自然排序方法。它是開源的,所以如果你想使用或看到它,它的地址如下:http://dev.projexsoftware.com/projects/projex
但是這個話題已經在論壇的其他地方討論過了,所以剛剛使用了庫中的方法。
什麼是圖像序列?你能給個例子嗎? – Blender 2012-08-08 00:10:28
是否所有文件名都以'picture_xxxx'的形式存在,或者是否有任何舊文件名混合? – 2012-08-08 00:36:58
可能是pic.xxxx.jpg或pic-xxx.jpg等我想讓腳本儘可能靈活以解釋不同的人的喜好 – 2012-08-08 02:47:02