如何檢查表單驗證在控制器中的Zend Framework 1.12

Question

如何檢查的形式進行驗證或沒有，我怎麼如果窗體沒有根據驗證

在ZF2我們顯示錯誤消息寫爲

userController 

$request = $this->getRequest(); 
$form = new Form_LoginForm(); 
if($request->isPost()){ 
    if($form->isvalid($this->_request->getPost())){ 
     $authAdapter = $this->getAuthAdapter(); 
     $username = 'john'; 
     $password = '123'; 
     $authAdapter->setIdentity($email) 
        ->setCredential($password); 
     $auth = Zend_Auth::getInstance(); 
     $result = $auth->authenticate($authAdapter); 
     if($result->isvalid()){ 
      $identity = $authAdapter->getResultRowObject(); 
      $authStorage = $auth->getStorage(); 
      $authStorage->write($identity); 
      $this->_helper->redirector(register/user); 
      echo 'valid'; 
     } else { 
      $this->view->errorMessage = "User name or password is incorrect"; 
     } 
    } 
} 

上面的代碼是在Zend中framework2，我需要的代碼在Zend framework 1.12。如何獲取的形式從login.phtml到UserController中，以及如何編寫代碼來檢查確認爲這是寫在Zend的framework2線4

我login.phtml形式是

<form action="<?php echo $this->url(array('controller'=>'user','action'=>'login'), 
    'default',true);?>" method="post"> 
    Email: <input type="text" name="user_email" type="email"   oninvalid="setCustomValidity('Plz enter valid email ')"  onchange="try{setCustomValidity('')}catch(e){}" required /> 
    Password: <input type="password" name="password" required /> 
    <input type="submit" name="submit" value="SUBMIT" /> 
    </form> 

Answer 1

如何像這樣....

$form   = new Form_LoginForm(); 

if ($this->getRequest()->isPost()) 
{ 
    if ($form->isValid($_POST)) 
    { 
     $formData  = $this->_getFormData(); 
     $authAdapter = $this->_getAuthAdapter($formData); 
     $auth   = Zend_Auth::getInstance(); 
     $result   = $auth->authenticate($authAdapter); 

     /** 
     * Authentication failed 
     */ 
     if (!$result->isValid()) 
     { 
      switch ($result->getCode()) 
      { 
       // Username doesn't exist 
       case Zend_Auth_Result::FAILURE_IDENTITY_NOT_FOUND : $yourLogic; 
                     break; 
       // Username and Password combination was incorrect 
       case Zend_Auth_Result::FAILURE_CREDENTIAL_INVALID : $yourLogic; 
                     break; 
       // General error message 
       default : $yourLogic; 
      } 
     } 
     /** 
     * Authentication success 
     */ 
     else 
     { 
      // Store the identity as an object where the password column has been omitted 
      $data = $authAdapter->getResultRowObject(null, 'password'); 
     } 
    } 
}