from datetime import datetime
class sms_store:
store = []
read = []
def add_new_arrival(self,number,time,text):
sms_store.read.append(len(sms_store.store))
sms_store.store.append(("From: {}, Recieved: {}, Msg: {}".format(number,time,text)))
def delete(self,i):
try:
del sms_store.store[i]
except IndexError:
print("Index is out of range. Cannot delete")
def message_count(self):
return print("Amt of messages in inbox: {}".format(len(sms_store.store)))
def viewall(self):
print(sms_store.store)
def get_unread_indexes(self):
#### ###################################I need help for this method.
def get_message(self,i)
print(sms_store.store[i])
### tests ####
time = datetime.now().strftime('%H:%M:%S')
my_inbox = sms_store() #instantiate an object 'store' for class
my_inbox.add_new_arrival("12345",time,"Hello how are you?") #instance of store object
my_inbox.add_new_arrival("1111111",time,"BYE BYE BYE")
my_inbox.viewall()
my_inbox.msgcount()
感謝您瀏覽本文。使用類和方法的Python短信商店程序 - has_been_viewed狀態
這是我需要做的:
my_inbox.add_new_arrival()
當添加一個新的消息,其has_been_viewed狀態設置爲False。以「已被視爲
my_inbox.get_unread_indexes()
返回所有還未看到短信
my_inbox.get_message(i)**
回報(FROM_NUMBER,time_arrived,text_of_sms)的消息的索引列表[我] 還改變其狀態」。 如果在位置i上沒有消息,則返回無
請幫助我解決上述問題!
非常感謝!